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Leokris [45]
2 years ago
6

Solve the problem.

Mathematics
1 answer:
prisoha [69]2 years ago
6 0

Answer:

The first can.

Step-by-step explanation:
formula: Pi x diameter x height

1st can has a volume of 113.10
2nd can has a volume of 75.40

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A rental company rents big-screen televisions for $22 down plus $4 a day. If the final bill is $46, how many days did you rent t
Misha Larkins [42]

Answer:  6 days

Step-by-step explanation:

take 22 off of the final price 46-22=24

now divid 24 by 4

and u have 6

4 0
3 years ago
15 qt/h =  gal/min plz I need help
Savatey [412]

1 gallon = 4 quarts.

15 quarts/ 4 = 3.75 gallons

1 hour = 60 minutes

3.75 gallons / 60 minutes = 0.625 gallons per minute.

7 0
3 years ago
3) The total cost is a function of how many pounds of candy that I buy.
Ray Of Light [21]

Total cost               independent variable

Pounds of candy    dependent variable

Step-by-step explanation:

A variable is a condition that is liable to change. Most experimental hypothesis use variables to draw up suitable statements to test.

  • An independent variable is that variable that does not rely on another variable. It induces the change or variation in another variable. In the statement above, the total cost is the independent variable.
  • The other variable which is the effect resulting from the  variation of the independent variable is the dependent variable. Here it is the number of pounds of the candy that changes when total cost varies.

Learn more:

Experiment brainly.com/question/1621519

#learnwithBrainly

8 0
3 years ago
Which of the following subsets of ℝ3×3 are subspaces of ℝ3×3? A. The 3×3 matrices whose entries are all greater than or equal to
Debora [2.8K]

Answer:

A. It is NOT a subspace of R^3x3

B. It IS a subspace of R^3x3

C. It IS a subspace of R^3x3

D. It is NOT a subspace of R^3x3

E  It is NOT a subspace of R^3x3

F.  It IS a subspace of R^3x3

Step-by-step explanation:

A way to show that a set is not a subspace, it´s enough to show that some properties of the definition of a vector spaces does not apply in that set or that operations under that set are not closed (we can get out of the set with linear combinations of elements in the set).

A. For definition of subspace, we know that every element has to have an additive inverse, but in set "A" (The 3×3 matrices whose entries are all greater than or equal to 0 ) every entry is greater than or equal to zero. In this set, there´s no additive inverse with the usual sum in R^3x3.

If sufficient to prove a set is a subspace showing that zero is in the set, there are additive inverses and that operations (sum and scalar multiplication) are closed in that set.

B.  Notice that the matrix 0 is in "B" (The 3×3 matrices A such that the vector (276) is in the kernel of A), also notice if A(276)=0 then -A(276)=0 so every additive inverse (of an element in "B") belongs to "B".

Now we just have to prove that operations are closed in "B". Let X,Y matrices in set "B" and let z a scalar from the field. We are going to show that:

zX+Y ∈ B

For definition of set B:

X(276)=0 and Y(276)=0

So for zX+Y:

(zX+Y)(276)=zX(276)+Y(276)=z(0)+(0)

(zX+Y)(276)=0

So (276) is in the kernel of zX+Y, i.e (zX+Y) ∈ B.

We conclude "B" (with usual sum and scalar product of matrices) is a subspace of R^3x3

C. Notice the matrix 0 ∈ "C" (The diagonal 3×3 matrices) and there are all the additive inverse of the elements in "C". With the usual sum and scalar product, if the only zero entries are above and under the diagonal, it´ll stay like that no matter what linear combination we do because sum of matrices is entry by entry, and for every entry above or under the diagonal the sum and scalar product of two elements is going to be 0 in the same entries under and above the diagonal. "C" is a subspace

D.  In set "D" (The non-invertible 3×3 matrices) it´s necessary to show that the sum is not closed:

Consider the following matrices and their sum:

X=\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&0\end{array}\right]\\ Y=\left[\begin{array}{ccc}0&0&0\\0&0&0\\0&0&1\end{array}\right]

X+Y=I

We showed that sum is not closed in "C", so "C" is not a subspace of R^3x3

E. The definition of a reduced row-echelon matrix requires that the first element of a row must be 1, but with sum and scalar multiplication is easy to show that these pivot could easily change its value. So the set "E" is not closed under the usual operations under R^3x3.

F. The argument is similar to part C. No matter what linear combination we do, the last row is always going to be zero (with the usual operations in R^3x3). 0 ∈ "F" (The 3×3 matrices with all zeros in the third row) and all additive inverses (for an element in "F") is in "F", we affirm that "F" is a subspace of R^3x3

5 0
2 years ago
After the Civil War, the era known as Reconstruction began. During this era, the federal government tried to grant rights to for
nikdorinn [45]

Answer:

D.

Step-by-step explanation:

Here is where the answer is mentioned: "After the Civil War, the era known as Reconstruction began. During this era, the federal government tried to grant rights to former slaves and rebuild the South."

8 0
2 years ago
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