Answer:
15/8 alphas = 1 gamma
Step-by-step explanation:
4 gammas = 5 beta
beta = 4/5 • gamma
2 betas = 3 alphas
beta = 3/2 • alpha
beta = beta
4/5 • gamma = 3/2 • alpha
multiply each side by 5/4
5/4 • 4/5 • gamma = 5/4 • 3/2 • alpha
gamma = 15/8 • alpha
Answer:
There is not sufficient evidence to conclude that there exists significant difference in the birth weights of a mother's first child and second child at 10% level of significance.
Step-by-step explanation:
When our p-value exceeds level of significance then we fail to reject our null hypothesis. In this scenario we are investigating if there exists significant difference in the birth weights of a mother's first child and second child and our null hypothesis is there exists no significant difference in the birth weights of a mother's first child and second child i.e.μd=0.
As we are given that p-value is greater than 10% level of significant so, we cannot reject our null hypothesis. Thus, the conclusion statement can be written as "There is not sufficient evidence to conclude that there exists significant difference in the birth weights of a mother's first child and second child at 10% level of significance."
Speed = Distance/Time
Time = Distance/Speed
Time = 17.6/11
= 1.6 hrs
<span>Multiply one of the equations so that both equations share a common complementary coefficient.
In order to solve using the elimination method, you need to have a matching coefficient that will cancel out a variable when you add the equations together. For the 2 equations given, you have a huge number of choices. I'll just mention a few of them.
You can multiply the 1st equation by -2/5 to allow cancelling the a term.
You can multiply the 1st equation by 5/3 to allow cancelling the b term.
You can multiply the 2nd equation by -2.5 to allow cancelling the a term.
You can multiply the 2nd equation by 3/5 to allow cancelling the b term.
You can even multiply both equations.
For instance, multiply the 1st equation by 5 and the second by 3. And in fact, let's do that.
5a + 3b = –9
2a – 5b = –16
5*(5a + 3b = -9) = 25a + 15b = -45
3*(2a - 5b = -16) = 6a - 15b = -48
Then add the equations
25a + 15b = -45
6a - 15b = -48
=
31a = -93
a = -3
And then plug in the discovered value of a into one of the original equations and solve for b.</span>