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d1i1m1o1n [39]
3 years ago
8

Expanded forma. 54896​

Mathematics
2 answers:
Semenov [28]3 years ago
6 0
  • 54896=<em><u>5</u></em><em><u>0</u></em><em><u>,</u></em><em><u>0</u></em><em><u>0</u></em><em><u>0</u></em><em><u>+</u></em><em><u>4</u></em><em><u>0</u></em><em><u>0</u></em><em><u>0</u></em><em><u>+</u></em><em><u>8</u></em><em><u>0</u></em><em><u>0</u></em><em><u>+</u></em><em><u>9</u></em><em><u>0</u></em><em><u>+</u></em><em><u>6</u></em>
maria [59]3 years ago
4 0

50000 4000 800 90 6

Step-by-step explanation:

this is the answer for the expanded form

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Need help fast!!!!!!
Alex17521 [72]

Answer:

if im correct i think the answer is y=1.25x-0.5

Step-by-step explanation:


7 0
3 years ago
At a local dealership 30% of cars are SUVs, 50% of the cars are painted white, and 15% are white and an SUV. If we randomly sele
alex41 [277]

Answer:

1/8, 0.0625 , or 6.25%

Step-by-step explanation:

50% of the cars are painted white.

1/2 * 1/2 = 1/4 * 1/4 = 1/8

Probability of A occuring 4 time(s) = 0.54 = 0.0625

Probability of A NOT occuring = (1 - 0.5)4 = 0.0625

Probability of A occuring = 1 - (1 - 0.5)4 = 0.9375

6 0
3 years ago
Y - X=-5<br> y = 2x2-3x-5<br> PLEASE HELP AND SHOW WORK <br> (substitution)
nikdorinn [45]

Answer:

Step-by-step explanation:

y - x = -5

y =  x-5

y = 2x² - 3x - 5

x-5 = 2x² - 3x - 5

2x² - 4x = 0

x² - 2x  = 0

x(x - 2) = 0

x = 2, 0

(x,y) = (2,-3), (0,-5)

8 0
2 years ago
Find the sum of -3a and 5a -3
zepelin [54]

Find the sum of -3a and 5a -3

-3a + (5a-3)

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3 years ago
Two random samples are taken, with each group asked if they support a particular candidate. A summary of the sample sizes and pr
Minchanka [31]

Answer:

And we got \alpha/2 =0.01 so then the value for \alpha=0.02 and then the confidence level is given by: Conf=1-0.02=0.98[/tex[ or 98%Step-by-step explanation:A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  The margin of error is the range of values below and above the sample statistic in a confidence interval.  Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  [tex]p_1 represent the real population proportion for 1

\hat p_1 =0.768 represent the estimated proportion for 1

n_1=92 is the sample size required for 1

p_2 represent the real population proportion for 2

\hat p_2 =0.646 represent the estimated proportion for 2

n_2=95 is the sample size required for 2

z represent the critical value for the margin of error  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})  

The confidence interval for the difference of two proportions would be given by this formula  

(\hat p_1 -\hat p_2) \pm z_{\alpha/2} \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}}  

For this case we have the confidence interval given by: (-0.0313,0.2753). From this we can find the margin of erro on this way:

ME= \frac{0.2753-(-0.0313)}{2}=0.1533

And we know that the margin of erro is given by:

ME=z_{\alpha/2} \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}}

We have all the values except the value for z_{\alpha/2}

So we can find it like this:

0.1533=z_{\alpha/2} \sqrt{\frac{0.768(1-0.768)}{92} +\frac{0.646 (1-0.646)}{95}}

And solving for z_{\alpha/2} we got:

z_{\alpha/2}=2.326

And we can find the value for \alpha/2 with the following excel code:

"=1-NORM.DIST(2.326,0,1,TRUE)"

And we got \alpha/2 =0.01 so then the value for \alpha=0.02 and then the confidence level is given by: Conf=1-0.02=0.98 or 98%

7 0
3 years ago
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