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Artemon [7]
3 years ago
7

The order of pairs below follow a pattern (0,2) , (1,3) , (2,4) , (3,5) , (4,6)

Mathematics
2 answers:
mote1985 [20]3 years ago
5 0

Answer:

i think it is the first one that is correct

i hope this helped

Step-by-step explanation:

Alik [6]3 years ago
4 0
The pattern is 1,1 is added each time
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Old McDonald had a farm. In one pen the old farmer had chickens and bulls together. In that pen there were 40 animals in total,
SVETLANKA909090 [29]

Answer:

There are 15 numbers of chicken and 25 numbers of bulls.

Step-by-step explanation:

The pen had chickens and bulls.  The pen contains 40 animals in total. The number of legs in the pen is 130 .

Let

a = number of chicken

b = number of bull

a + b = 40................(i)

A chicken has 2 legs and a bull has 4 legs.

The total legs can be represented as

2a + 4b = 130...........(ii)

combine the equation

a + b = 40................(i)

2a + 4b = 130...........(ii)

a = 40 - b

insert the value of a in equation(ii)

2(40 - b) + 4b = 130

80 - 2b + 4b = 130

80 + 2b = 130

2b = 130 - 80

2b = 50

divide both sides by 2

b = 50/2

b = 25

Insert the value of b in equation (i)

a + b = 40

a + 25 = 40

a = 40 - 25

a = 15

There are 15 numbers of chicken and 25 numbers of bulls.

8 0
3 years ago
Hi, I really need help with my homework please help
8090 [49]
Number one is 68 you have to divide on this download photomath its better because all you have to do is take a picture and it shows you how to do it ;)
5 0
3 years ago
Read 2 more answers
Complete the description of the slope of the line that joins the points
madam [21]

Step-by-step explanation:

the points are undefined

yeah I gotchuuu

5 0
3 years ago
Give an example of an addition problem in which you would and would not group the addenda differently to add
Ann [662]
Pemdas if you don't know what they are it looks like this.. (4+5)-5+4
similar to that..... 
I am pretty sure you wouldn't add that in a agenda because of the different properties it has but there are plenty more ways i just haven't figured them out 

8 0
3 years ago
SOLVING EACH SYSTEM BY ELIMINATION <br><br><br> x+3y=5 x=-6y+14<br><br><br> HELP
nata0808 [166]

Answer:

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

Step-by-step explanation:

Given the system of the equations

x+3y=5;\:x=-6y+14

solving by elimination method

\begin{bmatrix}x+3y=5\\ x=-6y+14\end{bmatrix}

\mathrm{Arrange\:equation\:variables\:for\:elimination}

\begin{bmatrix}x+3y=5\\ x+6y=14\end{bmatrix}

x+6y=14

-

\underline{x+3y=5}

3y=9

\begin{bmatrix}x+3y=5\\ 3y=9\end{bmatrix}

solve 3y=9 for y:

3y=9

\frac{3y}{3}=\frac{9}{3}

y=3

\mathrm{For\:}x+3y=5\mathrm{\:plug\:in\:}y=3

Solve x+3\cdot \:3=5 for x:

x+3\cdot \:3=5

x+9=5

x=-4

Therefore,

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

6 0
3 years ago
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