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swat32
3 years ago
9

△JKL has vertices at J(−2, 4), K(1, 6), and L(4, 4). Determine whether △JKL is a right triangle

Mathematics
2 answers:
Elan Coil [88]3 years ago
5 0

Step-by-step explanation:

hope helps you

have a nice day

adelina 88 [10]3 years ago
4 0

Answer:

Not a right triangle

Obtuse isosceles triangle.

Sides: J = 3.606   K = 6   L = 3.606

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Stacey had 3 cakes for her party, She had 1/8 of a cake left after the party. How much cake was eaten at her party?​
hoa [83]

Answer: 3=24/8 24/8 - 1/8 = 23/8 or 2 7/8

Step-by-step explanation:

Exchange 3 into 24/8 which is still 3 but in 8th’s. Then subtract 1/8 from 24/8 which is 23/8 or 2 7/8

8 0
3 years ago
Read 2 more answers
Assume that you want to test the claim that the paired sample data come from a population for which the mean difference is μd =
swat32

Answer:

Test statistic, t_{s} = -0.603 (to 3 dp)

Step-by-step explanation:

Deviation, d = x -y

Sample mean for the deviation

\bar{d} = \frac{\sum x-y}{n}

\bar{d} = \frac{(28-6) + (31-27)+(20-26)+(25-25)+(28-29)+(27-32)+(33-33)+(35-34)}{8} \\\bar{d} = -0.625

Standard deviation: SD = \sqrt{\frac{\sum d^{2} - n \bar{d}^2}{n-1}  }

\sum d^{2}  = (28-26)^2 + (31-27)^2 +(20-26)^2 +(25-25)^2 +(28-29)^2 +(27-32)^2 +(33-33)^2 +(35-34)^2\\\sum d^{2}  = 63

SD = \sqrt{\frac{63 - 8 *  (-0.625)^2}{8-1}  }

SD =2.93

Under the null hypothesis, the formula for the test statistics will be given by:

t_{s} = \frac{ \bar{d}}{s_{d}/\sqrt{n}  } \\t_{s} = \frac{- 0.625}{2.93/\sqrt{8}  }

t_{s} = -0.6033

6 0
3 years ago
What is the solution to the inequality below? w+4≤ -1
maxonik [38]

Answer:

w≤ -5

Step-by-step explanation:

hello :

w+4≤ -1

w+4-4≤ -1-7

w≤ -5

3 0
3 years ago
Please help me fast, best answer will get brainliest.​
Ipatiy [6.2K]

Answer:

Answer is below

Step-by-step explanation:

The outliers are 20 and 78 because they are not close to the other numbers. They have a great difference between them and the other numbers.

3 0
3 years ago
Simplify the expression: the square root of -13 times the square root of -26 calculator
Rasek [7]
Sqrt -13  = sqrt13 i
sqrt  -26  =  sqrt2 * sqrt13i 

sqrt-13 * sqrt -26  = sqrt2 * 13*  i^2  = -13 sqrt2 (because i^2 = -1)

answer is -13 sqrt2
6 0
3 years ago
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