Answer as a fraction: 17/6
Answer in decimal form: 2.8333 (approximate)
==================================================
Work Shown:
Let's use the two black points to determine the equation of the red f(x) line.
Use the slope formula to get...
m = slope
m = (y2-y1)/(x2-x1)
m = (4-0.5)/(2-(-1))
m = (4-0.5)/(2+1)
m = 3.5/3
m = 35/30
m = (5*7)/(5*6)
m = 7/6
Now use the point slope form
y - y1 = m(x - x1)
y - 0.5 = (7/6)(x - (-1))
y - 0.5 = (7/6)(x + 1)
y - 0.5 = (7/6)x + 7/6
y = (7/6)x + 7/6 + 0.5
y = (7/6)x + 7/6 + 1/2
y = (7/6)x + 7/6 + 3/6
y = (7/6)x + 10/6
y = (7/6)x + 5/3
So,
f(x) = (7/6)x + 5/3
We'll use this later.
---------------------
We ultimately want to compute f(g(0))
Let's find g(0) first.
g(0) = 1 since the point (0,1) is on the g(x) graph
We then go from f(g(0)) to f(1). We replace g(0) with 1 since they are the same value.
We now use the f(x) function we computed earlier
f(x) = (7/6)x + 5/3
f(1) = (7/6)(1) + 5/3
f(1) = 7/6 + 5/3
f(1) = 7/6 + 10/6
f(1) = 17/6
f(1) = 2.8333 (approximate)
This ultimately means,
f(g(0)) = 17/6 as a fraction
f(g(0)) = 2.8333 as a decimal approximation
The random sample of the students is an illustration of sampling
The chi-square test for goodness of fit is inappropriate because the variable under study is not categorical.
<h3>How to determine the reason chi square is not appropriate?</h3>
The dataset is given as:
Monday 34
Tuesday 29
Wednesday 32
Thursday 28
Friday 19
The variable of the above dataset is a not a categorical dataset.
One of the conditions of the chi-square test for goodness of fit test is that the variable under study must be categorical.
Hence, the chi-square test for goodness of fit is inappropriate because the variable under study is not categorical.
Read more about chi-square test at:
brainly.com/question/19959558
Answer:
Yes
Step-by-step explanation:
Linear means a line, and x is not squared or anything in this equation. If you were to graph it, it would be a line.
Answer:
Step-by-step explanation:
we know that
The compound interest formula is equal to
where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest in decimal
t is Number of Time Periods
n is the number of times interest is compounded per year
in this problem we have
substitute in the formula above
