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oee [108]
3 years ago
6

The reduction in cholesterol level after eating a certain brand of oatmeal for breakfast for one month in people with cholestero

l levels over 200 is Normally distributed, with mean (in milligrams) μ and standard deviation σ = 8 . Although the brand advertises that eating their oatmeal for breakfast daily for one month will produce a mean decrease in cholesterol of more than 20 points for people with cholesterol levels over 200, you believe that the mean decrease in cholesterol is actually less than advertised. To explore this, you test the hypotheses H0 : μ = 20 , H a : μ < 20 at the 0.05 level. You will randomly select 144 people with cholesterol levels over 200. After they eat this brand of oatmeal for one month, you will compute the mean decrease in cholesterol levels of the subjects.
If you observe a sample mean cholesterol reduction of ¯x = 18.52 , the P ‑value obtained is:

A. less than 0.01.
B. between 0.025 and 0.5.
C. between 0.05 and 0.1.
D. between 0.01 and 0.025.
Mathematics
1 answer:
Marysya12 [62]3 years ago
5 0
The answer is D. Between 0.01 and 0.025
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A projectile is fired at such an angle that the vertical
svetoff [14.1K]

(a) The projectile remains in the air for 10 seconds

(b) It travels a horizontal distance of 600 meters

Step-by-step explanation:

A projectile is fired at such an angle that

1. The vertical  component of its velocity is 49 m/sec

2. The horizontal  component of its velocity is 60 m/sec

We need to find:

(a) How long the projectile remains in the air

(b) The horizontal distance it travels

∵ The vertical distance y = u_{y} t - \frac{1}{2} g t², where

u_{y} is the vertical  component of its velocity, g is the acceleration

of gravity and t is the time

∵ y = 0 ⇒ it return to the same initial height

∵ u_{y} = 49 m/s

∵ g = 9.8 m/s²

- Substitute these values in the rule above

∴ 0 = 49 t - \frac{1}{2} (9.8) t²

∴ 0 = 49 t - 4.9 t²

- Take t as a common factor

∴ 0 = t (49 - 4.9 t)

- Equate each term by 0

∴ t = 0 ⇒ at initial position

∴ 49 - 4.9 t = 0

- Add 4.9 t to both side

∴ 49 = 4.9 t

- Divide both sides by 4.9

∴ t = 10 seconds

(a) The projectile remains in the air for 10 seconds

∵ The horizontal distance = u_{x} t, where u_{x} is the

   horizontal component of its velocity

∵ u_{x} = 60 m/sec

∵ t = 10 seconds

∴ x = 60 × 10 = 600 meters

(b) It travels a horizontal distance of 600 meters

Learn more:

You can learn more about the component of velocity in brainly.com/question/4464845

#LearnwithBrainly

3 0
3 years ago
NEED THIS ANSWER BY THE END OF THE DAY PLEASE HELP !!
Alborosie

Answer:

small number is 14

Larger number is 31

Step-by-step explanation:

Let x = one number

Let y = the second number

x + y = 45

x = y - 17

Put y - 17 into the top equation for x

y - 17 + y = 45

2y - 17 = 45          Add 17 to both sides

2y = 45 + 17

2y = 62                Divide by 2

y = 62/2

y = 31

3 0
3 years ago
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