Antelope: uniform motion => V = d/t => d = Vt = 7m/s * t
Lion: uniformly accelerated motion, with initial velocity = 0 => d = [1/2]a*t^2 = [1/2]*[5m/s^2]*t^2
7*t = 2.5*t^2=> 2.5t^2 - 7t =0 => t(2.5t - 7) = 0
2.5t - 7 = 0 => t = 7/2.5 = 2.8 m/s^2
Answer:
the cannonball’s velocity parallel to the ground is 86.6m/S
Explanation:
Hello! To solve this problem remember that in a parabolic movement the horizontal component X of the velocity of the cannonball is constant while the vertical one varies with constant acceleration.
For this case we must draw the velocity triangle and find the component in X(see atached image).
V= Initial velocity=100M/S

V= Initial velocity=100M/S
Vx=cannonball’s velocity parallel to the ground
Solving for Vx
Vx=Vcos30
Vx=(100m/S)(cos30)=86.6m/s
the cannonball’s velocity parallel to the ground is 86.6m/S
Answer:i
9E13 ELECTRONS
Explanation:
First we find the number of charges in two hrs
Which is - 2x 7200=- 14400NC
So no of electrons is now q/e
-144x10^-7/-1.6*10^-19
= 9*10^13
Nothing has been discovered to go faster than the speed of light. There have been some discoveries that had a speed very, very close to it (a bit under it), but none have passed it.