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SOVA2 [1]
3 years ago
9

A solenoid with an air core has a magnetic field pointing along its axis in the positive x direction. This solenoid is then fill

ed with a diamagnetic material. What changes will this make to the magnetic field along the axis of the solenoid?
Physics
1 answer:
trapecia [35]3 years ago
6 0

Answer:

we can say that with a smaller magnitude , the field will point is in same direction

Explanation:

we have given that

solenoid is filled with a diamagnetic material and with air, magnetic field pointing along its axis in the positive x direction

so in small magnitude, the field will point is in same direction

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Answer:

Force

Explanation:

The Force You Put Behind Said Apple Is Greater Than That Of Gravitational Pull

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3 years ago
Two transverse waves travel along the same taut string inopposite directions. the waves are described by following equations use
Umnica [9.8K]

Answer: y'=2Asin(kx)cos(wt)

Explanation:

Let y1=A sin (kx + wt) be the first wave

y2=A sin (kx - wt) be the second wave in the opposite direction (which we showed by putting a negative sign between the terms kx and wt)

Please do note that both wave have the same attributes (that's Amplitude, wave number and angular frequency) because they are formed on the same medium by the same source just that their directions are opposite.

By super imposing these 2 waves, we have a resulting singular wave representing both wave (law of superimposition) with a resulting value of vertical displacement y'.

Thus y' = y1 + y2.

Let us do the math.

y'=A sin (kx + wt) + A sin (kx - wt)

By factoring A out, we have that

y' = A [ sin (kx + wt) + sin (kx - wt)]

For simplicity let us use the substitution

Let (kx + wt) = a and (kx - wt) =b

Hence we have that

y' = A [sin a + sin b].

From trigonometric ratio

sin a + sin b = 2sin[(a+b)/2] * cos [(a - b)/2]

By recalling that (kx + wt) = a and (kx - wt) =b

sin a + sin b = 2sin [(kx +wt +kx-wt) /2] * cos [(kx +wt - (kx-wt))/2]

Thus we have that

sin a + sin b = 2sin [(kx+wt+kx-wt)/2] * cos[(kx+wt-kx+wt)/2]

By collecting like terms in the bracket we have that

sin a + sin b = 2sin[2kx/2] * cos [2wt/2]

By dividing

sin a + sin b = 2sin(kx) cos(wt)

Now let us get the final resultant vertical displacement (y')

Recall that

y' = A [sin a + sin b]. and we already deduced that

sin a + sin b = 2sin(kx) cos(wt)

Finally,

y' = A [2sin(kx) cos(wt)] which is

y'=2Asin(kx)cos(wt)...... Final answer

4 0
3 years ago
At what time after being ejected is the boulder moving at a speed 20.7 m/s upward?
Svetlanka [38]

The time after being ejected is the boulder moving at a speed 20.7 m/s upward is 2.0204 s.

<h3>What is the time after being ejected is the boulder moving at a speed 20.7 m/s upward?</h3>

The motion of the boulder is a uniformly accelerated motion, with constant acceleration

a = g = -9.8 $$m / s^2

downward (acceleration due to gravity).

By using Suvat equation:

v = u + at

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u = 40.0 m/s is the initial velocity

a = g = -9.8 $$m/s^2 is the acceleration

To find the time t at which the velocity is v = 20.7 m/s

Therefore,

$t=\frac{v-u}{a}=\frac{20.7-40}{-9.8}=2.0204 \mathrm{~s}

The time after being ejected is the boulder moving at a speed 20.7 m/s upward is 2.0204 s.

The complete question is:

A large boulder is ejected vertically upward from a volcano with an initial speed of 40.0 m/s. Ignore air resistance. At what time after being ejected is the boulder moving at 20.7 m/s upward?

To learn more about uniformly accelerated motion refer to:

brainly.com/question/14669575

#SPJ4

4 0
2 years ago
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