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Masteriza [31]
3 years ago
10

The route that Verlonda takes from her house to a store is represented on the grid below. Which ordered pair represents a point

on Verlonda's route?
Mathematics
1 answer:
Vadim26 [7]3 years ago
8 0

Answer:

(3.8)

Step-by-step explanation:

Given

See attachment for grid

Required

Which point is on Veronica's path

On the attached grid, I plotted each of the coordinate pair (i.e the given options, A to D) on the grid.

By observation. we can see that:

A is on the vertical line (y intercept)

B is on the second quadrant

C is just few points to the left of the given path

D represents Verlonda's house

<em>Hence, the required coordinate pair is: (3.8)</em>

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6 0
3 years ago
Find the sum without using a number line.<br> -8 1/6+2
Alina [70]

Answer:

Hi there!

Your answer is:

-35/6 OR -5 & 5/6

Step-by-step explanation:

-8 & 1/6

CHANGE TO IMPROPER FRACTION!

(-8*6 +1)/6

-48+1 / 6

-47 / 6

-47/6 + 2/1

CHANGE 2 SO IT HAS THE SAME DENOMINATOR

2/1 * 6/6

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-47/6 + 12/6

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Hope this helps

6 0
3 years ago
What type of graph is best to use to show data that are parts of a whole? A. Bar Graph B. Line Graph C. Histogram D. Circle Grap
Viktor [21]

Answer:

circle graph

Step-by-step explanation:


5 0
3 years ago
Read 2 more answers
2. What is the sample proportion of heads in your sample of 40? Report this value to your teacher.
Alexeev081 [22]

Answer:

\frac{18}{40}=0.45

Though it may vary, it's going closer to 0.5 as long as we enlarge our sample.

Step-by-step explanation:

1) Since a coin has heads and tails, then a sample proportion of 40 we can simulate it using some applets.

2) Here are the most common outcomes, as long as we continue on flipping coins.

\frac{18}{40}=0.45

If we continue enlarging our sample (80, 120,160...) the probability goes closer to 0.5

This shows: the theoretical probability goes closer and closer to the experimental probability of heads and tails

S_{80}=0.503\\S_{120}=0.50

6 0
3 years ago
How do you solve for a side in a right triangle that has a hypotenuse of 10, an angle of 35, and the side across from the angle
goblinko [34]

\sin \theta = \dfrac{\textrm{opposite}}{\textrm{hypotenuse}}

\sin 35^\circ = \dfrac{x}{10}

x = 10 \sin 35^\circ

That's the exact answer; they usually want a calculator approximation at this point,

x \approx 5.735

7 0
3 years ago
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