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stich3 [128]
3 years ago
14

Solve Formula for b: A =1/2bh

Mathematics
1 answer:
wolverine [178]3 years ago
3 0

Answer:

\huge \boxed{b =  \frac{2A}{h}}

Step-by-step explanation:

A =  \frac{1}{2} bh \\

Multiply through by 2 to eliminate the fraction

That's

2A = 2 \times  \frac{1}{2} bh \\ 2A = bh

Divide both sides by h to make b stand alone

\frac{2A}{h}  =  \frac{bh}{h}  \\

We have the final answer as

b =  \frac{2A}{h}  \\

Hope this helps you

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I have two bags. bag 1 contains 1010 blue marbles, while bag 2 contains 1515 blue marbles. i pick one of the bags at random, and
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55 blue or red marbles,

55-22 = 33 blue marbles

bag1+bag2= 2525

bag1=.4 

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bag 2=.6

so it is 40% that U choose bag 1 















6 0
3 years ago
Suppose that a regression line for some data transformed with logarithms predicts that when x equals 6, log(y) will equal 2.012.
KIM [24]

Answer:

102.8

Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
A rectangle has an area of 30 square meters and a perimeter of 34 meter. What are the dimensions of the rectangle?
Veseljchak [2.6K]
Rectangle's Perimeter is P=2(w+l)
where w and l are width and length respectively
34=2(w+l)
17=w+l
w=17-l

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now solve for l



8 0
3 years ago
A right triangle has side lengths of 20, 21, and 29 centimeters. The angle formed at the intersection of the 21 cm and 29 cm sid
Volgvan
The answer is 20/29 and 21-29
4 0
3 years ago
Which expression is equivalent to (4^5/4*4^1/4 divided by 4^1/2) ^1/2
hoa [83]

\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\\\ ~\hspace{7em}\textit{rational exponents} \\\\ a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} ~\hspace{10em} a^{-\frac{ n}{ m}} \implies \cfrac{1}{a^{\frac{ n}{ m}}} \implies \cfrac{1}{\sqrt[ m]{a^ n}} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \left( \cfrac{4^{\frac{5}{4}}\cdot 4^{\frac{1}{4}}}{4^{\frac{1}{2}}} \right)^{\frac{1}{2}}\implies \left( \cfrac{4^{\frac{5}{4}\cdot \frac{1}{2}}\cdot 4^{\frac{1}{4}\cdot \frac{1}{2}}}{4^{\frac{1}{2}\cdot \frac{1}{2}}} \right)\implies \cfrac{4^{\frac{5}{8}}\cdot 4^{\frac{1}{8}}}{4^{\frac{1}{4}}}\implies \cfrac{4^{\frac{5}{8}+\frac{1}{8}}}{4^{\frac{1}{4}}}

\bf \cfrac{4^{\frac{6}{8}}}{4^{\frac{1}{4}}}\implies \cfrac{4^{\frac{3}{4}}}{4^{\frac{1}{4}}}\implies 4^{\frac{3}{4}}\cdot 4^{-\frac{1}{4}}\implies 4^{\frac{3}{4}-\frac{1}{4}}\implies 4^{\frac{2}{4}}\implies 4^{\frac{1}{2}}\implies \sqrt{4}\implies 2

4 0
3 years ago
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