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3 years ago

10

If a fair coin is tossed 8 times, what is the probability, to the nearest thousandth, of getting exactly 2 tails?

1 answer:

xxMikexx [17]3 years ago

7 0

Answer:

0.109

Step-by-step explanation:

Probability is expressed by the number of desirable outcomes over the total outcomes. The total outcomes would be 2^8 because there are two possibilities in each flip, and using the fundamental counting principle, you get 2^8 total outcomes. Next, to find the amount of situations where you only flip two tails, you use 8 choose 2 because we are looking for the amount of ways you can choose 2 out of the 8 to be tails. 8 choose 2 is the same as:

8! / (6! x 2!) - 28

So, the probability is:

28 / 2^8 or 28/256

As a decimal, this is: 0.109375

And rounded to the nearest thousandth it's 0.109

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Y=(3/5)x -3 and 5y =3x-10 these lines are and the second question?

azamat

Look at the first line: y = (3/5)x - 3. What happens if you multiply each term by 5, to eliminate the fraction?

5y = 3x - 3

Compare this to the second equation,

5y - 3x = -10, or 5y = 3x - 10.

The coefficients of x and y (as 3 and 5 here) determine the slope of a straight line. Since 5y = 3x is present in both equations, the two lines MUST be parallel.

y = 4
4y = 6 => y = 6/4

y+4 and y =3/2 are both horizontal lines. Since they are horiz., they are parallel.

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3 years ago

Help!! Giving brainless need help

charle [14.2K]

Answer:

A. 15

Step-by-step explanation:

V of a right prism which this is. Is LxWxH

So 1.5x 4x2.5=15

4 0

3 years ago

Read 2 more answers

Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z

dexar [7]

Answer:

The value of the constant C is 0.01 .

Step-by-step explanation:

Given:

Suppose X, Y, and Z are random variables with the joint density function,

$f(x,y,z) = \left \{ {{Ce^{-(0.5x + 0.2y + 0.1z)}; x,y,z\geq0 } \atop {0}; Otherwise} \right.$

The value of constant C can be obtained as:

$\int_x( {\int_y( {\int_z {f(x,y,z)} \, dz }) \, dy }) \, dx = 1$

$\int\limits^\infty_0 ({\int\limits^\infty_0 ({\int\limits^\infty_0 {Ce^{-(0.5x + 0.2y + 0.1z)} } \, dz }) \, dy } )\, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y }(\int\limits^\infty_0 {e^{-0.1z} } \, dz }) \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0{e^{-0.2y}([\frac{-e^{-0.1z} }{0.1} ]\limits^\infty__0 }) \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}([\frac{-e^{-0.1(\infty)} }{0.1}+\frac{e^{-0.1(0)} }{0.1} ]) } \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}[0+\frac{1}{0.1}] } \, dy }) \, dx =1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2y} }{0.2}]^\infty__0 }) \, dx = 1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2(\infty)} }{0.2}+\frac{e^{-0.2(0)} }{0.2}] } \, dx = 1$

$10C\int\limits^\infty_0 {e^{-0.5x}[0+\frac{1}{0.2}] } \, dx = 1$

$50C([\frac{-e^{-0.5x} }{0.5}]^\infty__0}) = 1$

$50C[\frac{-e^{-0.5(\infty)} }{0.5} + \frac{-0.5(0)}{0.5}] =1$

$50C[0+\frac{1}{0.5} ] =1$

$100C = 1$ ⇒ $C = \frac{1}{100}$

C = 0.01

3 0

3 years ago

Factor pairs for 18 and

Solnce55 [7]

3,3,2 these are the primes of 18

4 0

4 years ago

Find a slope of the line that passes through (7,-4) and (81,92)

Leokris [45]

Answer:

48/37

Step-by-step explanation:

Use the formula (y1 - y2)/(x1 - x2).

Plug in your x and y values to get (92 + 4)/(81 - 7).

Simplify down to get 96/74 and simplify again to get 48/37.

5 0

3 years ago