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3 years ago

6

Please help me on this math question?

1 answer:

Whitepunk [10]3 years ago

5 0

M=30° because the right angle and 60 degree angle equal 150 and 180 (degrees in a triangle) minus 150 is 30

n=50° because 40 plus the right angle is 130 then the difference between that and 180 is 50 then n is the vertex angle of the one you found

t=98° because answer n plus the other part to the straight angle including the 112° angle is 68 then the total angle turns to 118 then the final angle turns to 62 via earlier reasoning, then because of another straight angle t=98

use the earlier reasoning to fine the other answers of

p=71°
q=39°

use the angle degrees formula to get Pentagon's maximum angles then use earlier resources

the final answers u should be able to figure out from there and u will never learn unless you do some yourself

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Answer:

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3 years ago

Solve for x: -2x – 7 = 3

oksian1 [2.3K]

Answer:

x=-5

Step-by-step explanation:

-2x=3+7

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3 years ago

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You have a wire that is 20 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The o

Aleksandr [31]

Answer:

Therefore the circumference of the circle is $=\frac{20\pi}{4+\pi}$

Step-by-step explanation:

Let the side of the square be s

and the radius of the circle be r

The perimeter of the square is = 4s

The circumference of the circle is =2πr

Given that the length of the wire is 20 cm.

According to the problem,

4s + 2πr =20

⇒2s+πr =10

$\Rightarrow s=\frac{10-\pi r}{2}$

The area of the circle is = πr²

The area of the square is = s²

A represent the total area of the square and circle.

A=πr²+s²

Putting the value of s

$A=\pi r^2+ (\frac{10-\pi r}{2})^2$

$\Rightarrow A= \pi r^2+(\frac{10}{2})^2-2.\frac{10}{2}.\frac{\pi r}{2}+ (\frac{\pi r}{2})^2$

$\Rightarrow A=\pi r^2 +25-5 \pi r +\frac{\pi^2r^2}{4}$

$\Rightarrow A=\pi r^2\frac{4+\pi}{4} -5\pi r +25$

For maximum or minimum $\frac{dA}{dr}=0$

Differentiating with respect to r

$\frac{dA}{dr}= \frac{2\pi r(4+\pi)}{4} -5\pi$

Again differentiating with respect to r

$\frac{d^2A}{dr^2}=\frac{2\pi (4+\pi)}{4}$ > 0

For maximum or minimum

$\frac{dA}{dr}=0$

$\Rightarrow \frac{2\pi r(4+\pi)}{4} -5\pi=0$

$\Rightarrow r = \frac{10\pi }{\pi(4+\pi)}$

$\Rightarrow r=\frac{10}{4+\pi}$

$\frac{d^2A}{dr^2}|_{ r=\frac{10}{4+\pi}}=\frac{2\pi (4+\pi)}{4}>0$

Therefore at $r=\frac{10}{4+\pi}$ , A is minimum.

Therefore the circumference of the circle is

$=2 \pi \frac{10}{4+\pi}$

$=\frac{20\pi}{4+\pi}$

4 0

3 years ago

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Pepsi [2]

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8 0

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Akimi4 [234]

Answer:

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7 0

3 years ago