Answer:

Step-by-step explanation:
we know that
In the triangle abc
if 
then

Because, the sum of the interior angles in a triangle must be equal to 180 degrees
therefore
Triangle abc is a right triangle
see the attached figure to better understand the problem
The sine of angle a is equal to divide the opposite side to angle a by the hypotenuse
so

The cosine of angle b is equal to divide the adjacent side to angle b by the hypotenuse
so

therefore

When two angles are complementary, the sine of one angle is equal to the cosine of the other angle and the cosine of one angle is equal to the sine of the other angle
so


Answer (2x + 7) • (x2 - 2)
Step-by-step explanation:
please give me brainlest!!
Step by step solution :
Step 1 :
Trying to factor as a Difference of Squares :
1.1 Factoring: x2-2
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : 2 is not a square !!
Ruling : Binomial can not be factored as the difference of two perfect squares.
Final result :
(2x + 7) • (x2 - 2)
Answer:
x = -7
Step-by-step explanation:
5x+8=3x-6
Subtract 3x from each side
5x-3x+8=3x-3x-6
2x+8 = -6
Subtract 8 from each side
2x+8-8 = -6-8
2x = -14
Divide by 2
2x/2 = -14/2
x = -7
The explorer's running velocity will be 1/3 the velocity of the train, 45/3 = 15.
From those issue statement, the train will a chance to be at the begin of the span The point when those voyagers have run 1/3 of the period of the span. In they run of the much end of the bridge, they will bring run 1/3 of the length of the span when those prepare achieves the close to wind. Beginning starting with those 1/3 point, they will make toward those 2/3 perspective At those prepare achieves those span. The prepare will travel the full period of the span in the the long haul it takes those voyagers to run those remaining 1/3. Accordingly the train must travel toward three times the running speed of the voyager. Train = 45 mph, voyagers = 15 mph.
The speed of P&D = 15 mph