Nolur acil lütfen yalvarırım yalvarırım lütfen yalvarırım sana
Answer:
K = 0,00000135 = 1.35 * 10^-6
Explanation:
Step 1: Data given
The equilibrium constant, K, for any reaction is defined as the concentrations of the products raised by their coefficients divided by the concentrations of the reactants raised by their coefficients. In this case, the concentrations are given as partial pressures.
The partial pressures of H2O = 0.0500 atm
The partial pressures of H2 = 0.00150 atm
The partial pressures of O2 = 0.00150 atm
Step 2: The balanced equation
2H2O(g) ⇆ 2H2(g) + O2(g)
Step 3: Calculate K
K = [O2][H2]² / [H2O]²
K = 0.00150 * 0.00150² / 0.0500²
K = 0,00000135 = 1.35 * 10^-6
Answer:
0.0970 M
Explanation:
Remember this equation:
mol/M x V
Convert it so that you can get M.
M=mol/V
Convert the 2.14 grams of H2SO4 into mols
=0.0218
Convert mL to L
225/1000
=0.225
Plug it in.
0.0218/0.225
=0.0970 M
<u>Answer:</u> Enzymes enhances the rate in the same order.
<u>Explanation:</u>
Catalyzed reactions are defined as the reactions in which a catalyst is used.
A catalyst is a substance which increases the rate of the reaction and does not participate in the reaction. It can be recovered at the end of the reaction. It decreases the activation energy of the reaction.
The rate of catalyzed reactions is always greater than the rate of uncatalyzed reactions.
Enzymes are the natural catalysts which are present in the animal body to increase the rate of some reactions.
Thus, they enhance the rate of both slow and fast uncatalyzed reaction at the same rate.