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Flauer [41]
3 years ago
5

The pH is given for three solutions. Calculate (H+] and [OH-] in each solution.

Chemistry
1 answer:
Georgia [21]3 years ago
8 0
H=8.9*10^-12
Oh=1.12*10^3
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How many milliliters of 0.260 m na2s are needed to react with 35.00 ml of 0.315 m agno3?
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The complete balanced chemical reaction is:

2 AgNO3 + Na2S --> 2 NaNO3 + Ag2S

 

First let us calculate the number of moles of AgNO3.

moles AgNO3 = 0.315 M * 0.035 L

moles AgNO3 = 0.011025 mol

 

From the reaction, 1 mole of Na2S is needed for every 2 moles of AgNO3 hence:

moles Na2S required = 0.011025 mol AgNO3 * (1 mol Na2S / 2 mol AgNO3)

moles Na2S required = 5.5125 x 10^-3 mol

 

Therefore volume required is:

volume Na2S = 5.5125 x 10^-3 mol / 0.260 M

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Answer:

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Na(s) + C(s, graphite) + 1/2 H₂(g) + 3/2 O₂(g) → NaHCO₃(s)

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