Answer:
C
Explanation:
the enthalpy of reaction is independent of the reaction path
I definitly believe the answer is c. 2
Answer: Thus the solubility of 
gas in water, at the same temperature, if the partial pressure of gas is 10.0 atm is 235mg/100g.
Explanation:-
The Solubility of 
in water can be calculated by Henry’s Law. Henry’s law gives the relation between gas pressure and the concentration of dissolved gas.
Formula of Henry’s law, 
.
= Henry’s law constant = ?
The partial pressure (P) of in water = 4.07 atm
\
At pressure of 10.0 atm
Thus the solubility of gas in water, at the same temperature, is 235mg/100g
Answer:3844 cm^2
Explanation:
62 squared since it is a square, and area is base times height
Answer:
The standard enthalpy of formation of this isomer of octane is -220.1 kJ/mol
Explanation:
Step 1: Data given
The combustion reaction of octane produces 5104.1 kJ per mol octane
Step 2: The balanced equation
C8H18(g) + 12.5 O2 ⟶ 8CO2 (g) + 9 H2O (g) ∆H°rxn = -5104.1 kJ/mol
Step 3:
∆H°rxn = ∆H°f of products minus the ∆H° of reactants
∆H°rxn = ∆H°f products - [∆H°f reactants]
-5104.1 kJ/mol = (8*∆H°fCO2 + 9*∆H°fH20) - (∆H°fC8H18 + 12.5∆H°fO2)
∆H°f C8H18 = ∆H°f 8CO2 + ∆H°f 9H2O+ 5104.1 kJ/mol
∆H°f C8H18 = 8 * (-393.5 kJ)/mol + 9 * (-241.8 kJ/mol)] + 5104.1 kJ
/mol
∆H°f C8H18 = -220.1 kJ/mol
The standard enthalpy of formation of this isomer of octane is -220.1 kJ/mol
