The question is in the attached word document.

A piece of aluminum weighing 10.0 grams is placed into a graduated cylinder that has an initial volume (before immersion) of 35.

padilas [110]

Answer:

The density of the metal sample is 2.70 $\frac{grams}{mL}$

Explanation:

Density is a magnitude that allows you to measure the amount of mass in a given volume of a substance. Then, the expression for the calculation of density is the ratio between the mass of a body and the volume it occupies:

$d=\frac{m}{V}$

Density, according to the International System of Units, is usually expressed in kilograms per cubic meter (kg / m3) or gram per cubic centimeter (g / cm3). Although it can also be expressed in any other unit of mass by volume.

So, for the calculation of density you know that:

mass of the sample= 10 grams
volume of the sample = volume on the cylinder after immersion - volume on the cylinder before immersion= 38.7 mL - 35.0 ml = 3.7 mL

Then:

$d=\frac{10 grams}{3.7 mL}$

d=2.70 $\frac{grams}{mL}$

The density of the metal sample is 2.70 $\frac{grams}{mL}$

5 0

3 years ago

A student develops the list shown below that includes laboratory equipment and materials for constructing a voltaic cell.

PSYCHO15rus [73]

Well this answer is not true and is false

3 0

4 years ago

A 8.06 g piece of solid CO 2 is allowed to sublime in a balloon. The final volume of the balloon is 1.00 L at 300.0 K. What is t

natka813 [3]

Answer:

The pressure of the gas is 4.428 atm.

Explanation:

Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

Considering a certain amount of ideal gas confined in a container where the pressure, volume and temperature can vary, but keeping the mass constant, that is, without altering the number of moles, the pressure, P, the temperature can be related, T and the volume, V, of an ideal gas using the ideal gas law:

P*V = n*R*T

where R is the ideal gas constant, and n is the number of moles of the gas.

In this case, to know n you must know the molar mass of the CO₂ compound. Being:

C: 12 g/mole
O: 16 g/mole

then, the molar mass of CO₂ is: 12 g/mole + 2*16 g/mole= 44 g/mole

Then you apply a rule of three: if 44 grams of CO₂ are present in 1 mole, 8.06 grams in how many moles are they?

$moles of CO_{2} =\frac{8.06 grams*1 mole}{44 grams}$

moles of CO₂= 0.18 moles

Then, you know:

P: ?
V: 1 L
n: 0.18 moles

R= 0.082 $\frac{atm*L}{mol*K}$

T= 300 K

Replacing in the equation of the ideal gas law:

P* 1 L= 0.18 moles* 0.082 $\frac{atm*L}{mol*K}$ * 300 K

Solving:

$P=\frac{0.18 moles* 0.082 \frac{atm*L}{mol*K} *300 K}{1 L}$

P= 4.428 atm

The pressure of the gas is 4.428 atm.

3 0

3 years ago

Which member of an ecosystem is responsible for capturing energy from the sun and turning it in to food ?

Gwar [14]

Answer:

a i think i hope this hepls

Explanation:

3 0

3 years ago

Read 2 more answers

Assuming ideal behavior, how many moles of argon would you need to fill a 14.0×12.0×10.0 ft room? assume atmospheric pressure of

Blababa [14]

We use the formula:

PV = nRT

First let us get the volume V:

volume = 14 ft * 12 ft * 10 ft = 1,680 ft^3

Convert this to m^3:

volume = 1680 ft^3 * (1 m / 3.28 ft)^3 = 47.61 m^3

n = PV / RT

n = (1 atm) (47.61 m^3) / (293.15 K * 8.21x10^-5 m3 atm / mol K)

n = 1,978.13 mol

4 0

3 years ago