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Mamont248 [21]
3 years ago
9

Proteins made by Rough ER travel to the golgi bodies in sacks called?

Chemistry
2 answers:
Alex73 [517]3 years ago
8 0
They are the little round things on er so that is ribosome

borishaifa [10]3 years ago
8 0
I believe proteins made by the Rough ER travel to the Golgi body in sacs called vesicles.
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Learning calculations in chemistry
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What question do u have?
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3 years ago
How is energy transfer different from energy transformation?
stepan [7]

Answer:

Transformation is into a different type of energy Ex: chemical to physical

Transfer is going to a to a place Ex: door knob to you

Explanation:

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5 0
3 years ago
When considering metal complexation with EDTA, if you are comparing 2 metals, the metal with a higher ____________ will react wi
DENIUS [597]

If you are comparing 2 metals, the metal with a higher <u>Number of free ions</u> will react with EDTA first

<h3>What is EDTA ?</h3>

EDTA is a type of chemical which binds certain metal ions such as calcium and magnesium. some of the functions of EDTA  includes:

  • Preventing blood clotting of blood samples
  • prevention of the formation of Biofilm by bacterias

The EDTA will readily react with metals which have a hiogher number of free ions that it can bind with.

Hence we can conclude that If you are comparing 2 metals, the metal with a higher <u>Number of free ions</u> will react with EDTA first.

Learn more about EDTA : brainly.com/question/10818175

7 0
2 years ago
HELP ASAP PLEASE<br> Use the word Precision in a sentence relating to chemistry!
Leno4ka [110]

Answer:

I needed to use good precision in my measurement for my chemistry lab

Explanation:

7 0
3 years ago
How many excess electrons must be added to an isolated spherical conductor 41.0 cmcm in diameter to produce an electric field of
alina1380 [7]

Answer:

3.65 x 10¹⁰ electrons

Explanation:

we'll apply the following equation for electric field of a point charge on a spherical conductor

E = k \frac{q}{r^{2} }

where E is the electric field

k is a constant of the value 8.99 x 10⁹ Nm²/C²

r is the radius of the spherical conductor

q is the total charge in the sphere

Given diameter d =41.0cm, radius r = 20.5cm = 0.205m (convert cm to m)

Electrical field E = 1250 N/C

we are asked to determine how many excess electrons must be added to the surface of the sphere to produce this electric field

E = k \frac{q}{r^{2} }

q = <u>E x r²</u>

        k

q =  <u>1250 N/C x 0.205m</u>²

       8.99 x 10⁹ Nm²/C²

q =   5.84 x 10⁻⁹ C

this is the total charge in the sphere

To determine the number of electrons, we can divide the charge q by the charge on an electron e (1.6 x 10⁻¹⁹C)

n = \frac{q}{e}

n = <u>5.84 x 10⁻⁹ C </u>

       1.6 x 10⁻¹⁹C

n = 3.65 x 10¹⁰ electrons

Therefore, to apply an electric field of magnitude 1250 N/C, the isolated spherical conductor must contain 3.65 x 10¹⁰ electrons

3 0
3 years ago
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