D is not because you can not graph it.
Answer:
Step-by-step explanation:
1. A
2. 6/10; 1/10
5's are in 10
6/10
Answer:
39 feet
Step-by-step explanation:
From the question;
let length of ladder =x feet
height of ladder will be=x-3 feet
ground distance of ladder bottom to building=15 feet
Applying Pythagorean relation
a²+b²=c²
where a=15 feet b=x-3 feet and c=x feet thus
x²-15²=(x-3)²
x²-225=x²-6x+9
collect like term
x²-x²-225-9=-6x
-234= -6x
x= 39 feet length of ladder
distance from ground to top of ladder= 39-3=36 feet
Answer:
The particle will travel 6 feet in first 2 seconds.
Step-by-step explanation:
We have been given that a particle moves according to the velocity equation 
. We are asked to find the distance that the particle will travel in its first 2 seconds.
Now, we will eliminate the absolute value sign as:
![s(t)=[\frac{6t^3}{3}-\frac{18t^2}{2}+12t]^1_0 +[\frac{-6t^3}{3}+\frac{18t^2}{2}-12t]^2_1](https://tex.z-dn.net/?f=s%28t%29%3D%5B%5Cfrac%7B6t%5E3%7D%7B3%7D-%5Cfrac%7B18t%5E2%7D%7B2%7D%2B12t%5D%5E1_0%20%2B%5B%5Cfrac%7B-6t%5E3%7D%7B3%7D%2B%5Cfrac%7B18t%5E2%7D%7B2%7D-12t%5D%5E2_1)
![s(t)=[2t^3-9t^2+12t]^1_0 +[-2t^3+9t^2-12t]^2_1](https://tex.z-dn.net/?f=s%28t%29%3D%5B2t%5E3-9t%5E2%2B12t%5D%5E1_0%20%2B%5B-2t%5E3%2B9t%5E2-12t%5D%5E2_1)
Therefore, the particle will travel 6 feet in first 2 seconds.
