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galina1969 [7]
3 years ago
10

PLEASE HELP ASAP NOW WILL MARK BRAINIEST LOTS OF POINTS!!!! HELP NOWWWWWWWWWWW 22. Explain why an sin^-1(sin(3pi/4))not equal 3p

i/4 when y=sin x and y=sin ^-1 are inverses. 25. Given f(x)=sin x and g(x)= cos x, find f(g(pi/2))=0. SHOW ALL YOUR STEPS.
Mathematics
1 answer:
NemiM [27]3 years ago
7 0

22. The range of the arcsine function (sin⁻¹(x)) is [-π/2, π/2]. The function will return π/4 for arcsin(sin(3π/4)) = arcsin(1/√2).

The sine function does not pass the horizontal line test, so it has no inverse over its entire domain. The arcsine function is only the inverse of the sine function over a limited domain/range.

25. sin(cos(π/2)) = sin(0) = 0.

As with any nested function evaluation, you evaluate the inner function first.

... cos(π/2) = 0

Then you evaluate the outer function.

... sin(0) = 0

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In isosceles right triangle ABC, point is on hypotenuse \overline{BC} such that \overline{AD} is an altitude of \triangle ABC an
Dmitriy789 [7]

Answer:

Area of triangle is 25.

Step-by-step explanation:

We have been given an isosceles right triangle

Isosceles triangle is the triangle having two sides equal.

Figure is shown in attachment

By Pythagoras theorem

BC^2=AC^2+AB^2

AD is altitude which divides the triangle into two parts

DC=5 implies BC =10 since D equally divides BC

Let AC=a implies AB=a being Isosceles

On substituting the values in the Pythagoras theorem:

10^2=a^2+a^2

100=2a^2

\Rightarrow a^2=50

\Rightarrow a=\pm5\sqrt{2}

WE can find area of right triangle by considering height AB and AD

Area of triangle ABC is:

\frac{1}{2}\cdot BC\cdot AD     (1)

\Rightarrow \frac{1}{2}\cdot 10\cdot AD

And other method of area of triangle is:

\frac{1}{2}\cdot AB\cdot BC       (2)

Equating (1) and (2) we get:

\frac{1}{2}\cdot 10\cdot AD=\frac{1}{2}\cdot a\cdot a

\Rightarrow AD=\frac{a^2}{10}

\Rightarrow AD=\frac{50}{10}=5

Using area of triangle is: \frac{1}{2}\cdot BC\cdot AD

Now, the area of triangle ABC=\frac{1}{2}\cdot 5\cdot 10

\Rightarrow 25



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