Normally, we could add exponents.
however, that only is possible when the bases are the same
recall what exponents mean
12³=12*12*12
so we cannot add exponents for 12³*11³ because that means 12*12*12*11*11*11
it would not equal 12⁶ or 11⁶
or you could refer to the rule
notice when x=x then we can add the bases
fun fact below
we can reverse a previous exponential rule like this
since
then
therefor
we can't add the exponents because the bases are not the same
Answer:
Step-by-step explanation:
we are given a square and rectangle.we want to figure out x which is the width of the rectangle. we are also given a condition i.e
- the area of the square equal to the area of the rectangle
therefore,
recall the formula of the area of square and rectangle so,
now assign variables
thus substitute:
simplify square:
divide both sides by 32:
and we're done!
Answer:
x intercept: (4,0)
y intercept: (0,2 1/2)
Step-by-step explanation:
Answer:
proof below
Step-by-step explanation:
Remember that a number is even if it is expressed so n = 2k. It is odd if it is in the form 2k + 1 (k is just an integer)
Let's say we have to odd numbers, 2a + 1, and 2b + 1. We are after the sum of their squares, so we have (2a + 1)^2 + (2b + 1)^2. Now let's expand this;
(2a + 1)^2 + (2b + 1)^2 = 4a^2 + 4a + 4b + 4b^2 + 4b + 2
= 2(2a^2 + 2a + 2b^2 + 2b + 1)
Now the sum in the parenthesis, 2a^2 + 2a + 2b^2 + 2b + 1, is just another integer, which we can pose as k. Remember that 2 times any random integer, either odd or even, is always even. Therefore the sum of the squares of any two odd numbers is always even.
Answer:
See Explanation
Step-by-step explanation:
The question is incomplete, as the sector, its area and the angle at the center are not given.
I will solve this using the following illusration
The area of a sector is:
Assume that:
The equation becomes
Simplify
Take: 
Cross Multiply
Solve for 
Take square roots
