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Allisa [31]
3 years ago
5

Not sure what number 3 is. Linear Relationships. Any help?

Mathematics
1 answer:
IgorC [24]3 years ago
5 0
The value of y varies directly with x, so \dfrac{y}{x}=\text{const}

We have:


\dfrac{y_1}{x_1}=\dfrac{y_2}{x_2}\\\\\\x_1=\dfrac{1}{4}\qquad y_1=25\qquad\qquad x_2=2\dfrac{1}{3}\qquad y_2=?\\\\\\
\dfrac{25}{\frac{1}{4}}=\dfrac{y_2}{2\frac{1}{3}}\\\\\\
100=\dfrac{y_2}{2\frac{1}{3}}\qquad|\cdot2\dfrac{1}{3}\\\\\\
100\cdot2\dfrac{1}{3}=y_2\\\\\\\boxed{y_2=233\frac{1}{3}}

Answer A)
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9.3x10^7 to regular notation
Dominik [7]

Answer:

93,000,000

Step-by-step explanation:

9.3x10^7

since the 10 has the ^7 on it, you move the decimal over 7 spots.

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3 years ago
If k is the midpoint of hj and hk =x+6 and hj =4x-6 then What does kj equal
leva [86]
Given: k= midpoint
hk=x+6
hj=4x-6

Remember midpoint cuts the segment hj in equal parts that means hk=kj and hk+kj=hj
hk+hk=hj
2hk=hj

2hk=hj
2 (x+6)=(4x-6)
2x+12=4x-6
2x-2x+12=4x-2x-6
12=2x-6
12+6=2x-6+6
18=2x
18/2=2x/2
9=x

hk=kj=x+6=(9)+6=15
kj=15
4 0
3 years ago
At the moment a hot cake is put in a cooler, the difference between the cake's and the cooler's temperatures is 50\degree50°50,
Len [333]

Answer:

D(t)=50\cdot (0.8)^{t}

Step-by-step explanation:

The equation for exponential decay function is given as:

D(t)=a(1-r)^{t}

where:

D(t)= difference in temperature t=time

r=rate of change

a =initial value of the temperature

From the given problem:

Initial Temperature,a=50°C

Rate of Decay,r=\frac{1}{5}

Therefore the function for the difference in temperature is given as:

D(t)=50(1-\frac{1}{5})^{t}

D(t)=50\cdot (\frac{4}{5})^{t}

We can convert \frac{4}{5} to decimal and write the function as:

D(t)=50\cdot (0.8)^{t}

7 0
3 years ago
Read 2 more answers
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