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3 years ago

PLEASEEEE help me on 3 4 & 5. it’s due before midnight

Mathematics

2 answers:

Juliette [100K]3 years ago

6 0

3. 78750
4. 0.000453
5. 0.00000089

Thepotemich [5.8K]3 years ago

6 0

Answer:

See below

Step-by-step explanation:

When changing from scientific notation to standard, you want to look at the exponent.

If exponent is positive, move decimal that many times to the right.

If negative, move to the left.

7.875 x 10^4

Exponent is positive so move to the right.

78750

4.53 x 10^-4

Exponent is negative so move to the left.

0.000453

8.9 x 10^-7

Exponent is negative so move to the left

.00000089

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2 years ago

Read 2 more answers

F(t)=t^2+19t+60<br> What are the zeros of the function and what is the vertex of the parabola?

SVEN [57.7K]

Answer: $-4,-15;\ \left(-\dfrac{19}{2},-\dfrac{121}{4}\right)$

Step-by-step explanation:

Given

Function is $F(t)=t^2+19+60$

Zeroes of the function are

$t^2+19t+60=0\\\\\Rightarrow t=\dfrac{-19\pm\sqrt{19^2-4\times 1\times 60}}{2\times 1}\\\\\Rightarrow t=\dfrac{-19\pm \sqrt{121}}{2}\\\\\Rightarrow t=\dfrac{-19\pm 11}{2}\\\\\Rightarrow t=-4,-15$

Using completing the square method

$y=t^2+2\times \dfrac{19}{2}t+\dfrac{19^2}{2^2}-\dfrac{19^2}{2^2}+60\\\\y=\left(t+\dfrac{19}{2}\right)^2+60-\dfrac{361}{4}\\\\y=\left(t+\dfrac{19}{2}\right)^2-\dfrac{121}{4}\\\\y+\dfrac{121}{4}=\left(t+\dfrac{19}{2}\right)^2\\\\\left(y-(-\dfrac{121}{4}\right)=\left(t-(-\dfrac{19}{2})\right)^2\\\\\text{The vertex is }\left(-\dfrac{19}{2},-\dfrac{121}{4}\right)$

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2 years ago

What’s the correct answer for this question?

g100num [7]

Answer:

Step-by-step explanation:

Volume of cone = 1/3πr²h

= (1/3)(3.14)(1.5)²(5)

= (1/3)(3.14)(2.25)(5)

= (1/3)(35.3)

= 11.78

≈ 11.8 cubic inches

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2 years ago