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sveta [45]
2 years ago
8

Write the equation of the line with a slope of 6 and pass-through (-2,-4)

Mathematics
1 answer:
faust18 [17]2 years ago
7 0

Answer:

y=6x+8

Step-by-step explanation:

y=mx+b

-4=6(-2)+b

-4=-12+b

8=b

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12.5 feet long weighs 158 pounds. How much does a piece of the same steel pipe 18.75
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237 pounds

Step-by-step explanation:

237 pounds

4 0
3 years ago
Arjun can type 40 words per minute.Dalia can type 55 words per minute.If Arjun and Dalia each type for 30 minutes,about how many
Citrus2011 [14]
♥ Solve:
(Arjun) 40*30=1200
(Dalia) 55*30=1650
Now subtract
1650-1200=450.
That means that Dalia will type 450 minutes more. 
Final answer: 450 

8 0
3 years ago
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Is the equation y=9x linear
ludmilkaskok [199]

Answer:

Linear

Step-by-step explanation:

A linear equation is an equation of a straight line, which means that the degree of a linear equation must be  0  or  1  for each of its variables. In this case, the degree of variable  y  is  1  and the degree of variable  x  is  1 .

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4 0
2 years ago
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A series of three? separate, adjacent tunnels is constructed through a mountain. Its length is approximately 25 kilometers. Each
Nadya [2.5K]

Answer:

312.5\pi \text{ km}^3\approx 981.75\text{ km}^3

Step-by-step explanation:

We have been given that a series of 3 separate, adjacent tunnels is constructed through a mountain. Its length is approximately 25 kilometers.

Each of the three tunnels is shaped like a half-cylinder with a radius of 5 meters.

Since we know that volume of a semicircular or a half cylinder is half the volume of a circular cylinder.

\text{Volume of a semicircular cylinder}=\frac{\pi r^2h}{2}, where,

r = Radius of cylinder,

h = height of the cylinder.

Upon substituting our given values in volume formula we will get,

\text{Volume of a semicircular cylinder}=\frac{\pi (5\text{ km})^2*25\text{ km}}{2}

\text{Volume of a semicircular cylinder}=\frac{\pi*25\text{ km}^2*25\text{ km}}{2}

\text{Volume of a semicircular cylinder}=\frac{\pi*625\text{ km}^3}{2}

\text{Volume of a semicircular cylinder}=\pi*312.5\text{ km}^3

\text{Volume of a semicircular cylinder}=\pi*312.5\text{ km}^3

\text{Volume of a semicircular cylinder}=981.74770\text{ km}^3

Therefore, the volume of earth removed to build the three tunnels is 312.5\pi \text{ km}^3\approx 981.75\text{ km}^3.


4 0
3 years ago
$6.53 Round to the nearest dollar
Alinara [238K]
It is $7. Anything average 5 you need to round up
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3 years ago
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