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2 years ago

Write the equation of the line with a slope of 6 and pass-through (-2,-4)

Mathematics

1 answer:

faust18 [17]2 years ago

7 0

Answer:

y=6x+8

Step-by-step explanation:

y=mx+b

-4=6(-2)+b

-4=-12+b

8=b

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A rectangular prism is a three-dimensional geometric figure, hollow or solid, contained by six rectangular sides that meet at ri

jenyasd209 [6]

Answer:B. C. D.

Step-by-step explanation:

8 0

2 years ago

A commuter crosses one of three bridges, A, B, or C, to go home from work. The commuter crosses bridge A with probability 1/3, c

mihalych1998 [28]

Answer:

0.1333 = 13.33% probability that bridge B was used.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Arrives home by 6 pm

Event B: Bridge B used.

Probability of arriving home by 6 pm:

75% of 1/3(Bridge A)

60% of 1/6(Bridge B)

80% of 1/2(Bridge C)

$P(A) = 0.75*\frac{1}{3} + 0.6*\frac{1}{6} + 0.8*\frac{1}{2} = 0.75$

Probability of arriving home by 6 pm using Bridge B:

60% of 1/6. So

$P(A \cap B) = 0.6*\frac{1}{6} = 0.1$

Find the probability that bridge B was used.

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.1}{0.75} = 0.1333$

0.1333 = 13.33% probability that bridge B was used.

8 0

3 years ago

Somebody help me plz!! It’s due tomorrow

Ilia_Sergeevich [38]

I think it is 50, the first one, you will count 6, on each link 4 more is added so when adding 11 more links it would be 44+6 which is 50

6 0

2 years ago

Can someone please help me I'm stuck on this question im in desperate need of help

kotegsom [21]

Answer:

Step-by-step explanation:

Point L's coordinates' difference is 7.

Point C's is 1.

Point H's is 2

And Point A's is 1

<em>Hope that helps!</em>

5 0

3 years ago

Read 2 more answers

: Naveen has a bag that contains 6 blue marbles, 3 green marbles, and 1 red marble. He will draw one marble randomly from the ba

loris [4]

Answer:

If Naveen wants to make sure that drawing a red marble is equally likely as drawing a different color marble, then he could add ***8 red marbles to the bag***

Step-by-step explanation:

The bag that contains 6 blue marbles, 3 green marbles, and 1 red marble.

Naveen wants to make sure that drawing a red marble is equally likely as drawing a different color marble, then he could add what?

Current total number of marbles = 10

Probability of drawing a red marble = (1/10)

Probability of drawing marble of other colour = (9/10)

And we want the the probability of drawing a red marble and one of the other marble to be the same.

This means we have to add a number of red marbles.

Let the number of red marbles to be added be n.

After adding n red marbles, the probability of drawing a red marble = (n+1)/(10+n)

Probability of drawing one of the other marbles = 9/(10+n)

And the probabilities are equal

(n+1)/(10+n) = 9/(10+n)

n+1 = 9

n = 9 - 1 = 8

This makes the number of red marbles 9 and total number of marbles 18.

The probability of drawing a red marble becomes (9/18) = 0.5

Probability of drawing a marble of other colour = (9/18) = 0.5 also.

4 0

3 years ago