We compute for the side lengths using the distance formula √[(x₂-x₁)²+(y₂-y₁)²].
AB = √[(-7--5)²+(4-7)²] = √13
A'B' = √[(-9--7)²+(0-3)²] = √13
BC = √[(-5--3)²+(7-4)²] = √13
B'C' = √[(-7--5)²+(3-0)²] =√13
CD = √[(-3--5)²+(4-1)²] = √13
C'D' = √[(-5--7)²+(0--3)²] = √13
DA = √[(-5--7)²+(1-4)²] = √13
D'A' = √[(-7--9)²+(-3-0)²] = √13
The two polygons are squares with the same side lengths.
But this is not enough information to support the argument that the two figures are congruent. In order for the two to be congruent, they must satisfy all conditions:
1. They have the same number of sides.
2. All the corresponding sides have equal length.
3. All the corresponding interior angles have the same measurements.
The third condition was not proven.
Answer:
The value of x is 7
Step-by-step explanation:
we know that
If two figures are congruent, then the corresponding angles and the corresponding sides are equal
In this problem
Triangles ABC and DEF are congruent
ABC≅DEF
therefore
AB=DE ----> equation A
AC=DF ----> equation B
BC=EF ----> equation C
Substitute the given values in the equation B
Solve for x
therefore
The value of x is 7
The draw in the attached figure
The answer is to multiply
Answer:
3
Step-by-step explanation:
The equation is y=Mx+b where m is the slope and b is the y intercept so m=3 so the slope is 3
Answer:
-3880
Step-by-step explanation:
Please give brainliest if this answer satisfies your question.
