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Mashutka [201]
3 years ago
9

Scientific notation of 10.34

Mathematics
2 answers:
snow_lady [41]3 years ago
7 0
Here is the answer that Siri gave me

Sav [38]3 years ago
7 0
1.034x 10 to the 1st power
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¿ sᴉɥʇ ǝʌlos ǝuoǝɯos uɐɔ
masha68 [24]

Answer:

1.9

{1.9}^{88888889}

Step-by-step explanation:

something to the power of 0 is 0, and for the other, you can't really do that number, it's a bit too big

4 0
2 years ago
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From 1929 through the early 1930s, the prices of consumer goods actually decreased. Economists call this phenomenon deflation. T
ludmilkaskok [199]

Answer:

23.42

Step-by-step explanation:

If something is decreasing by 7% we can mulitply it by (1-.07) or .93

so our formula is

100(.93)²⁰= 23.42388737

which rounds to 23.42

4 0
3 years ago
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Mark has 5 more pencils than Bill. If Mark has m amount of pencils, which expression gives the number of pencils Bill has?
mars1129 [50]

Answer:

m-5 Tray would be Bill's amount of pencils

5 0
2 years ago
If g(x)=6/(x-3) find g(5)
alexandr1967 [171]

Answer:

the answer is 3

Step-by-step explanation:

function notation is the way a function is written.

6 0
2 years ago
The hourly median power (in decibels) of received radio signals transmitted between two cities
trasher [3.6K]

Using the lognormal and the binomial distributions, it is found that:

  • The 90th percentile of this distribution is of 136 dB.
  • There is a 0.9147 = 91.47% probability that received power for one of these radio signals is  less than 150 decibels.
  • There is a 0.0065 = 0.65% probability that for  6 of these signals, the received power is less than 150 decibels.

In a <em>lognormal </em>distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{\ln{X} - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

  • The mean is of \mu = 3.5.
  • The standard deviation is of \sigma = \sqrt{1.22}

Question 1:

The 90th percentile is X when Z has a p-value of 0.9, hence <u>X when Z = 1.28.</u>

Z = \frac{\ln{X} - \mu}{\sigma}

1.28 = \frac{\ln{X} - 3.5}{\sqrt{1.22}}

\ln{X} - 3.5 = 1.28\sqrt{1.22}

\ln{X} = 1.28\sqrt{1.22} + 3.5

e^{\ln{X}} = e^{1.28\sqrt{1.22} + 3.5}

X = 136

The 90th percentile of this distribution is of 136 dB.

Question 2:

The probability is the <u>p-value of Z when X = 150</u>, hence:

Z = \frac{\ln{X} - \mu}{\sigma}

Z = \frac{\ln{150} - 3.5}{\sqrt{1.22}}

Z = 1.37

Z = 1.37 has a p-value of 0.9147.

There is a 0.9147 = 91.47% probability that received power for one of these radio signals is  less than 150 decibels.

Question 3:

10 signals, hence, the binomial distribution is used.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

For this problem, we have that p = 0.9147, n = 10, and we want to find P(X = 6), then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{10,6}.(0.9147)^{6}.(0.0853)^{4} = 0.0065

There is a 0.0065 = 0.65% probability that for  6 of these signals, the received power is less than 150 decibels.

You can learn more about the binomial distribution at brainly.com/question/24863377

5 0
2 years ago
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