Harper went into a movie theater and bought 10 bags of popcorn and 6 drinks,

Mathematics

1 answer:

Gnesinka [82]3 years ago

5 0

Answer:

The price of a drink = $4

The price of a bag of popcorn = $5.5

Step-by-step explanation:

Let p represent popcorn and d represent drink

Harper bought 10 bags of popcorn and 6 drinks and paid $79 ➡ 10p + 6d = $79

Damian bought 3 bags of popcorn and 5 drinks and paid $36.50 ➡ 3p + 5d = $36.50

Now multiply first equation by -3 and second equation by 10

-3 × (10p + 6d) = $79 ➡ -30p - 18d = -$237

10 × (3p + 5d) = $36.50 ➡ 30p + 50d = $365

Now add the new equationd

30p + 50d -30p - 18d = $365 - $237 (-30p will eliminate 30p)

32d = $128 divide both sides of the equation by 32

32 ÷ 32d = 32 ÷ $128 ➡ d = 4

If d = 4 that means a drink costs $4 we can use this information to find the price of a bag of popcorn

3p + 5d = $36.50 (replace d with 4)

3p + 4×5 = $36.50

3p + 20 = $36.50

3p = $36.50 - 20

3p = 16.50 divide both sides by 3

p = $5.5

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An owner of a key rings manufacturing company found that the profit earned (in thousands of dollars) per day by selling n number

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Answer:

The number of key rings sold on a particular day when the total profit is $5,000 is 4,000 rings.

Step-by-step explanation:

The question is incomplete.

An owner of a key rings manufacturing company found that the profit earned (in thousands of dollars) per day by selling n number of key rings is given by

$P=n^2-2n-3$

where n is the number of key rings in thousands.

Find the number of key rings sold on a particular day when the total profit is $5,000.

We have the profit defined by a quadratic function.

We have to calculate n, for which the profit is $5,000.

$P=n^2-2n-3=5\\\\n^2-2n-8=0$

We have to calculate the roots of the polynomial we use the quadratic equation:

$n=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\n= \frac{-2\pm\sqrt{4-4*1*(-8)}}{2}= \frac{-2\pm\sqrt{4-32}}{2} = \frac{-2\pm\sqrt{36}}{2} =\frac{-2\pm6}{2} \\\\n_1=(-2-6)/2=-8/2=-4\\\\n_2=(-2+6)/2=4/2=2$