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svet-max [94.6K]
3 years ago
14

Create a table of values for the function f(x) = (1/3)^–x

Mathematics
1 answer:
mr_godi [17]3 years ago
5 0

Answer:

See the explanation

Step-by-step explanation:

The function given to us is:

f(x) = (1/3)⁻ˣ

We can convert the negative power into positive one by interchanging the numerator and denominator.

f(x) = (3/1)ˣ

f(x) = 3ˣ

Substitute value for x= -3 , -2, -1, 0, 1, 2, 3

f(-3) = 3⁻³ = 0.037

f(-2) = 3⁻² = 0.111

f(-1) = 3⁻¹ = 0.333

f(0) = 3⁰ = 1

f(1) = 3¹ = 3

f(2) = 3² = 9

f(3) = 3³ = 27

f(4) = 3⁴ = 81

and so on

The table of the found values of f(x) or y for the corresponding values of x, along with their graph is given below.

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Answer: (x-7)^2+(y+2)^2=11^2 ; A=121\pi

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I have never done a problem like this, so this is my first time attempting it.

The standard form for the equation of a circle is:

(x-a)^2+(y-b)^2=r^2

Begin by grouping the 'x' terms and 'y' terms:

(x^2-14x)+(y^2+4y-68)=0

Complete the square for the second polynomial:

(\frac{b}{2} )^2=(\frac{4}{2} )^2=4

(x^2-14x)+(y^2+4y+4-4-68)=0

(x^2-14x)+(y^2+4y+4)-4-68=0

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Do the exact same process with the other polynomial:

(x^2-14x-72)+(y+2)^2=0

Complete the square:

(\frac{14}{2} )^2=49

(x^2-14x+49-49-72)+(y+2)^2=0

(x^2-14x+49)-49-72+(y+2)^2=0

(x^2-14x+49)-121+(y+2)^2=0

(x-7)^2-121+(y+2)^2=0

Bring the 121 to the other side to get:

(x-7)^2+(y+2)^2=121

(x-7)^2+(y+2)^2=11^2

The above expression is the equation of our circle in standard form. It is centered at the coordinates (7, -2) and has a radius of 11 units. The area of a circle if given by:

A=\pi r^2=121\pi

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