25x² + 1 = 5
25x² + 1 - 5 = 0
25x² - 4 = 0 By difference of two squares
(5x)² - (2)² = 0
(5x - 2)(5x + 2) = 0
5x - 2 = 0 or 5x + 2 = 0
5x = 0 + 2 5x = 0 - 2
5x = 2 5x = -2
x = 2/5 x = -2/5
x = 0.4 x = -0.4
x = + 0.4 or -0.4
Step-by-step explanation:
26. x²+5x+25/4 = (x + 5/2)²
29. x²/4y²-2/3+4y²/9x² = (x/2y - 2y/3x)²
(x -1)(x +4) = 0
x² +3x -4 = 0 . . . . . . probably the form you're looking for
Answer:
x = 3
Step-by-step explanation:
Square both sides of the equation
(x - 3)(x - 5) = 0
x = 3 or 5
Now, you must always check your results because a result may not satisfy the original equation.
If x = 3, then 
and 3 - x = 3 - 3 = 0
So 3 satisfies the original.
If x = 5, then 
, but 3 - x = 3 - 5 = -2. Therefore, 5 does NOT satisfy the original equation.
That means that x = 3 is the solution to the equation.
5.B
6.D
7.A
8.B
9.A
10.C hsvs whehsg
