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dlinn [17]
3 years ago
12

Gregory estimated the product of two decimals to be 24.

Mathematics
2 answers:
saveliy_v [14]3 years ago
8 0

D.) 5.9(3.92)

Explanation:        (→ = estimated)

5.9 → 6

3.92 → 4

6 x 4 = 24

thus, D, 5.9(3.92), is your answer.

Vesnalui [34]3 years ago
4 0

Answer:

it is the last one 5.9(3.92)

Step-by-step explanation:

i just took the exact same Assignment and got the question right soo....

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1. 14=7b<br> 2. -11=k/4<br> 3.6z=-6
Romashka-Z-Leto [24]

Answer:

the anwer is 14-2294-dhi2

Step-by-step explanation:

Because 14 is - 4 you multiple to 5 equal= dhi2

3 0
2 years ago
How do you do these questions?
Alika [10]

Answer:

a) - 7 dollars

b) 24.30 dollars

c) - 5 dollars

Step-by-step explanation:

b) 27 / 10%

Divide 27 by 10/100 by multiplying 27 by the reciprocal of 10/100.

27 x 100/10

Multiply 27 and 100 to get 2700.

2700/10

Divide 2700 by 10 to get 270.

270

Divide 270 by 100 to get 2.7

Subtract 27.00 - 2.7 = 24.30

24.30

4 0
2 years ago
If f(x)=3x^2+1 and g(x) =1-x, what is the truly value of (f-g)(2)
Lilit [14]

Answer:

14

Step-by-step explanation:

f(x)=3x²+1

f(2) = 3 x 2² + 1 = 13

g(x) =1-x

g(2) = 1 - 2 = -1

(f-g)(2) f(2) - g(2) = 13 - (-1) = 14

8 0
2 years ago
What is 20 5/81 in simplest form
Marizza181 [45]
20 5/81 in its simplest form is 20 5/81.

20 5/81 originally looks like this ⇒ 1625/81

((20 * 81)+5)/81 = (1620+5)/81 = 1625/81   * this is an improper fraction because the numerator is greater than the denominator. Improper fractions must be converted to proper fractions. It will then become a mixed fraction.
 
     <u>  0020  5/81</u>        
81 | 1625
       <u>162      </u>      * 81 x 2
           05

5 0
2 years ago
A particle moves along the x-axis so that at any time t, t ≥ 0, its acceleration is a(t) = -4sin(2t). If the velocity of the par
sasho [114]

The velocity of the particle is given by

v(t)=v(0)+\displaystyle\int_0^ta(u)\,\mathrm du

Since a(t)=-4\sin2t and v(0)=7, we get

\displaystyle\int_0^ta(u)\,\mathrm du=\int_0^t-4\sin2u\,\mathrm du=2\cos2u\bigg|_0^t=2\cos2t-2

\implies v(t)=2\cos2t+5

Similarly, the position function is obtained via

x(t)=x(0)+\displaystyle\int_0^tv(u)\,\mathrm du

We know v(t) and we're told that x(0)=0, so

\displaystyle\int_0^tv(u)\,\mathrm du=\int_0^t(2\cos2u+5)\,\mathrm du=\sin2u+5u\bigg|_0^t=\sin2t+5t

\implies x(t)=\sin2t+5t

making the answer A.

3 0
2 years ago
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