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3 years ago

PLEASE HELP!!

Chemistry

1 answer:

tensa zangetsu [6.8K]3 years ago

6 0

Answer:

Explanation:

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Which list of formulas represents compounds, only?

Ann [662]

The best formula that represents compounds only is <span>CO2, H2O, NH3.</span>

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3 years ago

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A flexible container at an initial volume of 3.10 L contains 9.51 mol of gas. More gas is then added to the container until it r

Schach [20]

Answer:

49.09 moles of gas are added to the container

Explanation:

Step 1: Data given

Initial volume = 3.10 L

Number of moles gas = 9.51 moles

The final volume = 19.1 L

The pressure, temperature remain constant

Step 2: Calculate number of moles gas

V1/n1 = V2/n2

⇒with V1 = the initial volume of the gas = 3.10 L

⇒with n1 = the initial number of moles = 9.51 moles

⇒with V2 = the increased volume = 19.1 L

⇒with n2 = the final number of moles gas

3.10L / 9.51 moles = 19.1 L / n2

n2 = 58.6 moles

The new number of moles is 58.6

Step 3: calculate the number of moles gas added

Δn = 58.6 - 9.51 = 49.09 moles

49.09 moles of gas are added to the container

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3 years ago

An instrument that allows you to look closely at objects that are invisible to the human eye, including cells

xxMikexx [17]

The answer is Microscope

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3 years ago

Initial alcohol is converted to compound A. Compound A undergoes three different transformations. Name compound A and each the f

nikklg [1K]

<h2>Acetic Acid</h2>

Explanation:

Initial alcohol that is formed from methane is methanol that can be converted to acetic acid.

Methanol in presence of $CO_2$ and hydrogen gas gets oxidized to acetic acid with the release of water.

Hence, compound A will be Acetic acid.

$CH_3OH + CO_2 +H_2$ → $CH_3COOH + H_2O$

The acetic acid formed can be transformed into -

$CH_3COOH$ → $CH_4 + CO$

The product formed is methane and carbon monoxide.

2. $CH_3COOH$ → $CH_2CHO + H_2O$

The product formed is formaldehyde and water.

3. $CH_3COOH + NaHCO_3$ → $CH_3COONa +CO_2 +H_2O$

The product formed is sodium acetate, carbon dioxide, and water.

4 0

3 years ago

You wish to make a 0.285 M hydroiodic acid solution from a stock solution of 12.0 M hydroiodic acid. How much concentrated acid

Inessa05 [86]

The amount, in mL, of the concentrated acid required, would be 1.1875 mL

<h3>Dilution</h3>

From the dilution equation:

m1v1=m2v2 where m1 and m2 = molarity before and after dilution, and v1 and v2 = volume before and after dilution.

m2 = 0.285M, m1 = 12.0M v2 = 50.0 mL

v1 = m2v2/m1 = 0.285x50/12 = 1.1875 mL

Thus, 1.1875 mL of the acid would be taken and diluted with water up to the 50 mL mark.

More on dilution can be found here: brainly.com/question/13949222

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2 years ago