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Mademuasel [1]
3 years ago
15

Complete the table to summarize the properties of the different subatomic particles. Type in your answers.

Chemistry
2 answers:
Aloiza [94]3 years ago
4 0

<h2>Complete the table to summarize the properties of the different subatomic particles. </h2>

Explanation:

Atom

It is a smallest particle which cant exist independently.

According To Dalton, atom was indivisible but later on, it was proved that atom can be subdivided into sub atomic particles called electron, proton & neutron.

These subatomic particles have marked properties .

Proton

  • It was discovered by E.Goldstein .
  • It is positively charged particle
  • It is present in nucleus .
  • Its mass is equal to 1.6726219 × 10⁻²⁷ kilograms

Neutron

  • It was discovered by E.chadwick .
  • It is neutral
  • It is present inside the nucleus .
  • It's mass is equal to 1.674927471×10⁻²⁷ kg

Electron

  • It was discovered by J.J Thomson .
  • It has negative charge .
  • It's mass is equal to 9.10938356 × 10⁻³¹ kilograms
  • It is present outside the nucleus in shells .
natulia [17]3 years ago
3 0

A: 1

B: 1

C: 0.0006

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Answer:

See explanation below

Explanation:

The melting point (the temperature that it changes from solid to liquid) of a pure substance depends on its mass, the forces between its molecules, and the pressure of the system.

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A sample of C3H8 has 3.28 × 1024 H atoms. How many carbon atoms does the sample contain? What is the total mass of the sample in
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How many grams are in 0.572 moles of glucose, C6H12O6
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Answer:

103.00

Explanation:

1 mole of Glucose

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3. Balance each of the following redox reactions in the listed aqueous environment. (4 pts each, 8 pts total) Crs)NO3 (a) Cr (a)
GrogVix [38]

Explanation:

(a)   The given reaction equation is as follows.

        Cr(s) + NO^{-}_{3}(aq) \rightarrow Cr^{3+}(aq) + NO(g) (acidic)

So, here the reduction and oxidation-half reactions will be as follows.

Oxidation-half reaction: Cr(s) \rightarrow Cr^{3+}(aq) + 3e^{-}

Reduction-half-reaction: NO^{-}_{3} + 3e^{-}(aq) \rightarrow NO(g)

As total charge present on reactant side is -1 and total charge present on product side is +3. And, since it is present in aqueous medium. Hence, we will balance the charge for this reaction equation as follows.

      Cr(s) + NO^{-}_{3}(aq) + 4H^{+}(aq) \rightarrow Cr^{3+}(aq) + NO(g) + 2H_{2}O(l) (acidic)

(b)   The given reaction equation is as follows.

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So, here the reduction and oxidation-half reactions will be as follows.

Reduction-half reaction: HCO^{-}_{3}(aq) + 4e^{-} \rightarrow H_{2}CO(aq)

Oxidation-half reaction: Ag(s) \rightarrow Ag(NH_{3})^{+}_{2}(aq) + 1e^{-}

Hence, to balance the number of electrons in this equation we multiply it by 4 as follows.

      4Ag(s) \rightarrow 4Ag(NH_{3})^{+}_{2}(aq) + 4e^{-}

Therefore, balancing the whole reaction equation in the basic medium as follows.

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