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VARVARA [1.3K]
3 years ago
9

Someone please help me!!

Chemistry
1 answer:
sesenic [268]3 years ago
4 0

Answer:

the 3rd one (0.01 cm the one selected already)

Explanation:

copper wire isn't excessively big, and it wraps around the pencil because its malleable. I think that the most accurate would be 0.01 cm

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Read 2 more answers
Answer the following questions…
Zina [86]

The concentration of the hydronium ion in hydrochloric acid is 0.0045 M, and the pH of the solution is 2.34.

<h3>What is pH?</h3>

pH is the potential of the hydrogen or the hydronium ions in the aqueous solution.

As the solution contains 4.5 \times 10^{-3} \;\rm  M\; HCl the concentration of the hydronium ion will be the same, 4.5 \times 10^{-3} \;\rm  M.

The pH of the solution is calculated as:

\begin{aligned} \rm pH &= \rm -log[H^{+}]\\\\&= - \rm log (4.5 \times 10^{-3})\\\\&= 2.34\end{aligned}

The concentration of the hydroxide ion is calculated from pH and hydronium ion as:

\begin{aligned} \rm [H_{3}O^{+}][OH^{-}] &= 10^{-14}\\\\&= \dfrac{1 \times 10^{-14}}{4.5 \times 10^{-3}}\\\\&= 2.2 \times 10^{12}\end{aligned}

Now, for the calcium hydroxide solution, the calculations are shown as,

\begin{aligned} \rm (H_3}\rm O^{+}) &= \rm antilog (-pH)\\\\&= \rm antilog (-8)\\\\&= 10^{-8} \;\rm M\end{aligned}

pOH is calculated as:

\begin{aligned} \rm pOH &= 14- 8 = 6\\\\\rm [OH^{-}] &=  \rm antilog (-6)\\\\&= 10^{-6} \end{aligned}

The concentration of calcium hydroxide is calculated as:

\begin{aligned} &= \dfrac{1}{2} \times \rm [OH^{-}]\\\\&= 5 \times 10^{-4} \;\rm M\end{aligned}

Therefore, the pH and the pOH give the concentration of the hydrogen or the hydronium ion and the hydroxide ion.

Learn more about pH and pOH here:

brainly.com/question/16062632

#SPJ1

3 0
2 years ago
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