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Alja [10]
3 years ago
9

Solve for y q(a+y)=67y+93

Mathematics
1 answer:
stepan [7]3 years ago
4 0
Step 1: Add -67y to both sides.
aq+qy+−67y=67y+93+−67y

aq+qy−67y=93

Step 2: Add -aq to both sides.
aq+qy−67y+−aq=93−aq

qy−67y=−aq+93

Step 3: Factor out variable y.
y(q−67)=−aq+93
Step 4: Divide both sides by q-67.
y(q−67)/q−67=. -aq+93/q−67
y=−aq+93/q−67
Answer:
y=−aq+93/q−67
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Step-by-step explanation:

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2 years ago
Two planes leave an airport at noon. If the eastbound plane flies at 560 mph and the westbound plane flies at 500 mph, at what t
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3 years ago
Solve the equation for x
PIT_PIT [208]

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Step-by-step explanation:

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4 years ago
What are the solution of the equation x^2- 4x -32 = 0 ?show your work and justify each step.
soldier1979 [14.2K]
X^2-4x-32=0

(x+a)(x+b)

x^2-(a+b)x+ab

a+b=4
ab=-32

a=-b+4
(-b+4)b=-32

-b^2+4b=-32
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If b=8, a=-4
If b=-4, a= 8

Plug in a and b to (x+a)(x+b)
x= -4, 8
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3 years ago
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