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3 years ago

9

Solve for y q(a+y)=67y+93

1 answer:

stepan [7]3 years ago

4 0

Step 1: Add -67y to both sides.
aq+qy+−67y=67y+93+−67y

aq+qy−67y=93

Step 2: Add -aq to both sides.
aq+qy−67y+−aq=93−aq

qy−67y=−aq+93

Step 3: Factor out variable y.
y(q−67)=−aq+93
Step 4: Divide both sides by q-67.
y(q−67)/q−67=. -aq+93/q−67
y=−aq+93/q−67
Answer:
y=−aq+93/q−67

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3 years ago

If g(x)=7x²−4x−3 and h(x)=5x²−12x, find (h∘g)(1)<br><br><br>FIRST BEST ANSWER BRAINLIEST

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Answer: See below

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$h\:\circ \:g=h\left(g\left(x\right)\right)$

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3 years ago

Ryan is trying a low-carbohydrate diet. He would like to keep the amount of carbs consumed in grams between the levels shown in

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The solution and interpretation of the inequality is:

<em /> $x > 50$ <em> and </em> $x < 150$ <em>. Ryan needs to consume more than 50 grams of carbohydrates, but less than 150 grams of carbohydrates.</em>

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3 years ago

What is the variable x in 40+10x=5x-30

konstantin123 [22]

40 + 10x = 5x - 30

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3 years ago