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2 years ago

(1×10,000)+(3×100)+(5×10)+(9× 10 1 )+(8× 100 1 ) as a decimal number.

Mathematics

1 answer:

andrey2020 [161]2 years ago

8 0

Answer: $19,267.0$

Step-by-step explanation:

1. You have the following information given in the problem above:

$(1*10,000)+(3*100)+(5*10)+(9*101)+(8*1001)$

2. To solve this exercise, first you must multiply the number that ar inside the parentheses and then you must add all of them, as you can see below:

$10,000+300+50+909+8008=19,267$

3. Rewriting is as a decimal, you have that the answer is:

$19,267.0$

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3 years ago

Priya is hosting a poetry club meeting this week and plans to have fruit punch and cheese for the meeting. She is preparing 8 ou

Korvikt [17]

Answer:

i) Number of people in club = 12

ii) 96 ounces of fruit punch for 12people

iii) 24 ounces of cheese for 12 people

iv) Priya's budget for poetry club meeting in dollars = $7.87

Step-by-step explanation:

We are not given the options for the equations that could represent the quantities and constraints in this situation. We can tell we are to represent the information given above.

Number of people in the club = 12

8 ounces of fruit punch per person

For 12 people = 12×8 = 96 ounces of fruit punch

2 ounces of cheese per person

For 12 people = 12×2 = 24 ounces of cheese

A package of cheese = 16 ounces

The costs for 1package = $3.99

The costs for 16 ounces of cheese = $3.99

The cost for 24 ounces of cheese = (24×3.99)/16 = 5.985

The cost for 24 ounces of cheese = $5.99

One-gallon jug of fruit punch = 128 ounces

The cost of One-gallon jug of fruit punch = $2.50

The costs of 128 ounces of fruit punch = $2.50

The costs for 96 ounces of fruit punch = (96×2.5)/128 = 1.875

The costs for 96 ounces of fruit punch = $1.88

Priya's budget for poetry club meeting in dollars = $5.99 + $1.88 = $7.87

Cost per item for x number of people:

y = x(2.5/128) + x (3.99/16)

y = x(0.0195) + x(0.2494)

Cost equation for Priya's budget:

y = 96x(2.5/128) + 24x (3.99/16)

y = 96x(0.0195) + 24x(0.2494)

Since the total number of people to attend the meeting is 12, the constraint = 0≤x≤12

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2 years ago

For what value of constant c is the function k(x) continuous at x = 0 if k =

nlexa [21]

The value of constant c for which the function k(x) is continuous is zero.

<h3>What is the limit of a function?</h3>

The limit of a function at a point k in its field is the value that the function approaches as its parameter approaches k.

To determine the value of constant c for which the function of k(x) is continuous, we take the limit of the parameter as follows:

$\mathbf{ \lim_{x \to 0^-} k(x) = \lim_{x \to 0^+} k(x) = 0 }$

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}= c }$

Provided that:

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}= \dfrac{0}{0} \ (form) }$

Using l'Hospital's rule:

$\mathbf{\implies \lim_{x \to 0} \ \ \dfrac{\dfrac{d}{dx}(sec \ x - 1)}{\dfrac{d}{dx}(x)}= \lim_{x \to 0} sec \ x \ tan \ x = 0}$

Therefore:

$\mathbf{\implies \lim_{x \to 0 } \ \ \dfrac{sec \ x - 1}{x}=0 }$

Hence; c = 0

Learn more about the limit of a function x here:

brainly.com/question/8131777

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1 year ago

(1×10,000)+(3×100)+(5×10)+(9× 10 1 ​ )+(8× 100 1 ​ ) as a decimal number.

(1×10,000)+(3×100)+(5×10)+(9× 10 1 )+(8× 100 1 ) as a decimal number.