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3 years ago

99 POINTS, NEED HELP WITH ALGEBRA

Mathematics

2 answers:

densk [106]3 years ago

7 0

Answer:

ofc

Step-by-step explanation:

Tanya [424]3 years ago

4 0

1 is in picture above.

$average \: rate = \frac{f(4) - f(1)}{4 - ( - 1)} = \frac{5}{4 - ( - 1)} = 1$

3. In the picture...

4. In the picture...

5. Parts A and B are true.

$average \: rate = \frac{f(0) - f( - 10)}{0 - ( - 10)} = \frac{( - 6) - 184}{0 - ( - 10)} = \frac{ - 190}{10} = - 19$

7. The axis symmetry equation of

$y = a {x}^{2} + bx + c$

$x = \frac{ - b}{2a}$

So it would be x=-3/4

$y = {(x - 6)}^{2} + 10$

T=(6, 10) vertex coordinates...

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3 years ago

Find the rational zeros of the polynomial function, f(x)= 4x^3-8x^2-19x-7

Dima020 [189]

Answer:

The rational zero of the polynomial are $\pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1$ .

Step-by-step explanation:

Given polynomial as :

f(x) = 4 x³ - 8 x² - 19 x - 7

Now the ration zero can be find as

$\dfrac{\textrm factor of P}{\textrm factor Q}$ ,

where P is the constant term

And Q is the coefficient of the highest polynomial

So, From given polynomial , P = -7 , Q = 4

Now , $\dfrac{\textrm factor of \pm P}{\textrm factor of \pm Q}$

I.e $\dfrac{\textrm factor of \pm P}{\textrm factor of \pm Q}$ = $\frac{\pm 7 , \pm 1}{\pm 4 ,\pm 2,\pm 1 }$

Or, The rational zero are $\pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1$

Hence The rational zero of the polynomial are $\pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1$ . Answer

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4 years ago

5. It took Kiara 35.25 minutes to finish her chores on Saturday, while it took her brother Derek

cestrela7 [59]

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3 years ago

Chris is packing toy boxes that are cubes with 4 inch-sides into a crate. The crate is 3 feet wide by 3 feet long by 2 feet tall

STALIN [3.7K]

Answer:

$486\ toy\ boxes$

Step-by-step explanation:

we know that

$1\ ft=12\ in$

step 1

Convert the dimensions of the boxes to feet

$4\ in=4/12=(1/3)\ ft$

step 2

Find the volume of the toy boxes

$V=b^{3}$

$V=(1/3)^{3}=(1/27)\ ft^{3}$

step 3

Find the volume of the crate

$V=LWH$

$V=(3)(3)(2)=18\ ft^{3}$

step 4

Divide the volume of the crate by the volume of the toy boxes to find the number of toy boxes

$\frac{18}{(1/27)}= 486\ toy\ boxes$

7 0

3 years ago

Find two numbers, if Their sum is −7 and their difference is 14

Schach [20]

let those numbers be x and y

According to your question

x + y = -7

x - y =14

adding both equations

2x = 7

or x = 7/2

substitute value of x in either equation

y = -21/2

So,

x= 7/2

y=-21/2

Hope this helps!

Thanks

7 0

4 years ago