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beks73 [17]
3 years ago
13

F(x)=2x^2-x+1 find the vertex

Mathematics
1 answer:
Galina-37 [17]3 years ago
5 0

The Answer fam is (1/4,7/8)

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Suppose astronomers built a 50-meter telescope. how much greater would its light-collecting area be than that of the 10-meter ke
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Answer: Its light-collecting area would be 25 times greater than that of the 10-meter keck telescope.

Step-by-step explanation:

1. To solve this problem you must apply the formula for calculate the area of a circle, which is shown below:

A=r^{2}\pi

Where<em> r</em> is the radius of the circle.

2. The diameter of a circle is:

D=\frac{r}{2}

Where <em>r</em> is the radius of the circle.

3. Therefore, keeping this on mind, you have that the light-collecting area of a  50-meter keck telescope is:

A_1=(\frac{50m}{2})^{2}\pi=1963,49m^{2}

4. And the light-collecting area of a 10-meter keck telescope is:

A_2=(\frac{10m}{2})^{2}\pi=78.53m^{2}

5. Divide A_1 by A_2, then:

\frac{1963.49m^{2}}{78.53m^{2}}=25

6. Therefore, its light-collecting area would be 25 times greater than that of the 10-meter keck telescope.

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