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Gwar [14]
3 years ago
10

Solve this absolute value equation and show all work.

Mathematics
1 answer:
vitfil [10]3 years ago
6 0
I was confused at first until I realized that you'd shared not one, not two, but three questions in one post.  would you please post just one question at a time to avoid this.

I'll focus on your second question only:  Solve <span>3 + |2x - 4| = 15.

Subtr. 3 from both sides.  Result:  |2x - 4| = 12

Divide all terms by 2, to reduce:    |x - 2| = 6

Case 1:  x-2 is already +, so we don't need |    |:

                       x - 2 = 6    =>   x = 8 (first answer)

Case 2:  x-2 is negative, so |2x-4| = -(2x-4) = 6

             Then   -2x + 8 = 6.  Subtr. 8 from both sides:   -2x = -2

               Div both sides by -2:  x = 1 (second answer)

Be sure to check these results by subst. them into the original equation.

Please post your other questions separately.  Thanks and good luck!

</span>
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Find the exact value of cos(sin^-1(-5/13))
son4ous [18]

bearing in mind that the hypotenuse is never negative, since it's just a distance unit, so if an angle has a sine ratio of -(5/13) the negative must be the numerator, namely -5/13.

\bf cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right] \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{then we can say that}~\hfill }{sin^{-1}\left( -\cfrac{5}{13} \right)\implies \theta }\qquad \qquad \stackrel{\textit{therefore then}~\hfill }{sin(\theta )=\cfrac{\stackrel{opposite}{-5}}{\stackrel{hypotenuse}{13}}}\impliedby \textit{let's find the \underline{adjacent}}

\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{13^2-(-5)^2}=a\implies \pm\sqrt{144}=a\implies \pm 12=a \\\\[-0.35em] ~\dotfill\\\\ cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right]\implies cos(\theta )=\cfrac{\stackrel{adjacent}{\pm 12}}{13}

le's bear in mind that the sine is negative on both the III and IV Quadrants, so both angles are feasible for this sine and therefore, for the III Quadrant we'd have a negative cosine, and for the IV Quadrant we'd have a positive cosine.

8 0
3 years ago
A fencing company charges $22 per foot to install a wood fence. How much will it cost to install a wood fence around a rectangul
borishaifa [10]
20+20+38+38=116

116×22 = 2552

It will cost $2,552 to install the wood fence.
4 0
3 years ago
HELP HELP I NEED HELP ASAP
tia_tia [17]
I am pretty sure the answer is 180
5 0
3 years ago
Can someone pls help me answer this :/​
eimsori [14]

Answer:

y = - \frac{3}{2} x + 6

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + b ( m is the slope and b the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (0, 6) and (x₂, y₂ ) = (4, 0) ← 2 points on the line

m = \frac{0-6}{4-0} = \frac{-6}{4} = - \frac{3}{2}

Since the line crosses the y- axis at (0, 6) ⇒ b = 6

y = - \frac{3}{2} x + 6 ← equation of line

5 0
3 years ago
Can someone please help me find the measure of angle ABO?
lara [203]

Answer:

m<ABO = 22 deg

Step-by-step explanation:

A tangent intersects a circle at the point of tangency making a right angle with the radius drawn to that point. That means that <BAO is a right angle and measures 90 deg. That makes the other two angles of the triangle complementary with a sum of 90 deg.

m<O + m<B = 90

68 + m<B = 90

m<B = 22

Answer: m<ABO = 22 deg

3 0
3 years ago
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