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Gwar [14]
3 years ago
10

Solve this absolute value equation and show all work.

Mathematics
1 answer:
vitfil [10]3 years ago
6 0
I was confused at first until I realized that you'd shared not one, not two, but three questions in one post.  would you please post just one question at a time to avoid this.

I'll focus on your second question only:  Solve <span>3 + |2x - 4| = 15.

Subtr. 3 from both sides.  Result:  |2x - 4| = 12

Divide all terms by 2, to reduce:    |x - 2| = 6

Case 1:  x-2 is already +, so we don't need |    |:

                       x - 2 = 6    =>   x = 8 (first answer)

Case 2:  x-2 is negative, so |2x-4| = -(2x-4) = 6

             Then   -2x + 8 = 6.  Subtr. 8 from both sides:   -2x = -2

               Div both sides by -2:  x = 1 (second answer)

Be sure to check these results by subst. them into the original equation.

Please post your other questions separately.  Thanks and good luck!

</span>
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Please help thank you
Elodia [21]

Answer:

a1 = 6

a2 = 15

a3 = 24

a4 = 33

Step-by-step explanation:

Let k =1

a1 =-3 +9(1) = -3 +9 = 6

Let k = 2

a2 = -3 +9(2) =-3+18 = 15

Let k =3

a3 =-3 +9(3) = -3 +27 = 24

Let k = 4

a4 = -3 +9(4) =-3+36 = 33

8 0
3 years ago
Jay is 3 years less than 4 times Nelly’s age ( n ). Which expression represents Jay’s age?
NeX [460]

Answer:

9

Step-by-step explanation: 3x4= 12  -3=9

6 0
3 years ago
Read 2 more answers
PLS ANSWER ASAPThe function f(x) = 4x + 10 models the amount of money Francis makes
Andrei [34K]

Answer:

A 18

Step-by-step explanation:

f(x) = 4x + 10

f(2) = 4(2) + 10

f(2) = 8 + 10

f(2) = 18

6 0
3 years ago
How to write this standard form?<br><br> 2y=-3x+5
Schach [20]

Answer:

3x + 2y - 5 = 0

Step-by-step explanation:

Standard form: ax + by + c = 0

2y = -3x + 5

+3x - 5 to both sides

2y + 3x - 5 = 0

Change order.

3x + 2y - 5 = 0

4 0
3 years ago
Read 2 more answers
Given cosα = −3/5, 180 &lt; α &lt; 270, and sinβ = 12/13, 90 &lt; β &lt; 180
torisob [31]

I got

-  \frac{6 3}{65}

What we know

cos a=-3/5.

sin b=12/13

Angle A interval are between 180 and 270 or third quadrant

Angle B quadrant is between 90 and 180 or second quadrant.

What we need to find

Cos(b)

Cos(a)

What we are going to apply

Sum and Difference Formulas

Basics Sine and Cosines Identies.

1. Let write out the cos(a-b) formula.

\cos(a - b)  =  \cos(a)  \cos(b)  +  \sin(a)  \sin(b)

2. Use the interval it gave us.

According to the given, Angle B must between in second quadrant.

Since sin is opposite/hypotenuse and we are given a sin b=12/13. We. are going to set up an equation using the pythagorean theorem.

.

{12}^{2}  +  {y}^{2}  =  {13}^{2}

144 +  {y}^{2}  = 169

25 =  {y}^{2}

y = 5

so our adjacent side is 5.

Cosine is adjacent/hypotenuse so our cos b=5/13.

Using the interval it gave us, Angle a must be in the third quadrant. Since cos is adjacent/hypotenuse and we are given cos a=-3/5. We are going to set up an equation using pythagorean theorem,

.

( - 3) {}^{2}  +  {x}^{2}  =  {5}^{2}

9 +  {x}^{2}  = 25

{x}^{2}  = 16

x = 4

so our opposite side is 4. sin =Opposite/Hypotenuse so our sin a =4/5.Sin is negative in the third quadrant so

sin a =-4/5.

Now use cosine difference formula

-  \frac{3}{5}  \times  \frac{5}{13}  +   - \frac {4}{5}  \times  \frac{12}{13}

- \frac{15}{65} + (  - \frac{48}{65}  )

-  \frac{63}{65}

Hope this helps

6 0
3 years ago
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