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saul85 [17]
3 years ago
13

The volume of a cylinder is given by the formula

="V+ \pi r^2h" alt="V+ \pi r^2h" align="absmiddle" class="latex-formula">, where r is the radius of the cylinder and h is the height. Suppose a cylindrical can has radius (x + 8) and height (2x + 3). Which expression represents the volume of the can?
Mathematics
2 answers:
n200080 [17]3 years ago
4 0
V = \pi  r^{2}h where r is radius and h is height

so when radius is (x+8) and height is (2x+3),

volume = \pi  (x+8)^{2}(2x+3)
liq [111]3 years ago
3 0
Since your trying to find the volume of a cylinder and this is your formula V = πr²h you would write the equation with ( x + 8 ) as your radius and ( 2x + 3 ) as your height. The final equation for this would be π ( x + 8 )² ( 2x + 3) that would be the proper equation.
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Answer:

$12.49

Step-by-step explanation:

The price right now = 0.8 * the original price

9.99 = 0.8*x

x=12.4875

x≈12.49

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What are angles that are equal called?
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Question 5
navik [9.2K]

Answer:

A. Similar using SAS; ∆ABC ~ ∆DFE

Step-by-step explanation:

m<B of ∆ABC = m<F of ∆DFE

AB corresponds to DF

AB/DF = 12/8 = 3/2

BC corresponds to FE

BC/FE = 24/16 = 3/2

Thus, the ratio of the corresponding sides of both triangles are the same. Therefore, both triangles has two sides that are proportional to each other, and also had an included corresponding angles that are congruent to each other.

By the SAS criterion, we can conclude that both triangles are similar to each other. That is, ∆ABC ~ ∆DFE

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Find the midpoint of the line segment with the endpoints (1, 0) and (2, -10).
Mariulka [41]

Answer:

\bigl(\frac{3}{2},-5\bigr)

or in decimal form

(1.5,-5)

Step-by-step explanation:

The midpoint of the line with endpoints (x_1,y_1) and (x_2,y_2) is \bigl(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\bigr). just take the average between the points

so given the points (1,0) and (2,-10)

x_1=1

y_1=0

x_2=2

y_2=-10

the midpoint is found as follows:

\bigl(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\bigr)

\bigl(\frac{1+2}{2},\frac{0-10}{2}\bigr)

\bigl(\frac{3}{2},\frac{-10}{2}\bigr)

\bigl(\frac{3}{2},-5\bigr)

or in decimal form

(1.5,-5)

7 0
3 years ago
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