Question

During an experiment, the percent yield of calcium chloride from a reaction was 85.22%. Theoretically, the expected amount should have been 113 grams. What was the actual yield from this reaction? CaCO3 + HCl → CaCl2 + CO2 + H2O
96.3 grams
99.0 grams
113 grams
121 grams

Answer 1

The formula to find yield is

(Actual Yield)/(Theorectical Yield) x100

Just do the math.

85.22% x 113 = 96.2986

Convert it to 3 significant figures

Ans: 96.3g

Answer 2

Answer : The actual yield of the reaction is, 96.3 g

Explanation :  Given,

Percent yield of the reaction = 82.22 %

Theoretical yield of the reaction = 113 g

The formula used for the percent yield will be :

$\text{Percent yield}=\frac{\text{Actual yield}}{\text{Theoretical yield}}\times 100$

or,

$\text{Actual yield}=\frac{(\text{Percent yield}\times \text{Theoretical yield})}{100}$

Now put all the given values in this formula, we get:

$\text{Actual yield}=\frac{(85.22\times 113)}{100}=96.3g$

Therefore, the actual yield of the reaction is, 96.3 g