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The answer is B ......... good luck
(a) The mass of hydrogen sulfide produced in the reaction is 9.44 g.
(b) Water is the limiting reagent in the given reaction.
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Mass of hydrogen sulfide produced</h3>
Al2S3 + 6H2O ---> 2Al(OH)3 + 3H2S
mass of water in the reaction = 6(18 g/mol) = 108 g/mol
mass of hydrogen sulfide in the reaction: = 3(34) = 102 g/mol
108 g/mol of H2O ------- > 102 g/mol of H2S
10 of H2O -----------> ?
= 9.44 g
Aluminum sulfide will be completely consumed by the reaction while some fraction of water will remain. Thus, water is the limiting reagent in the given reaction.
Learn more about limiting reagents here: brainly.com/question/26905271
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Hope this might help a little
Answer:
1.14 moles of oxygen will react
Explanation:
The balanced equation of reaction between iron and oxygen is
4 Fe + 3 O₂ → 2 Fe₂O₃
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:
- Fe: 4 moles
- O₂: 3 moles
- Fe₂O₃: 2 moles
The molar mass of iron being Fe 55.85 g/mole, then the following amount of mass reacts by stoichiometry: 4 moles* 55.85 g/mole=223.4 g
You can apply the following rule of three: if by stoichiometry 223.4 grams of Fe react with 3 moles of O₂, 84.9 grams of Fe react with how many moles of O₂?

moles of O₂= 1.14 moles
<u><em>1.14 moles of oxygen will react</em></u>
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