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Aleksandr [31]
3 years ago
10

The Arrhenius plot of the reaction has a downward slope of 1.5 x104. Calculate the time required to reduce the concentration of

A to 10% of its original value at 100oC. g
Chemistry
1 answer:
madam [21]3 years ago
4 0
1.5?10000 10% then add it up
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Is boron an element a compound a heterogeneous mixture or a homogeneous mixture?
liberstina [14]
The answer is heterogeneous mixture<span> because the </span>blood<span> cells are physically separate from the </span>blood<span> plasma.</span>
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What is a bond between a positive and negative ion called?
BartSMP [9]
B) ionic bond

(although in reality, every bond is fundamentally the sharing of a pair of electron. but due to unmutal electonegativity, the molecule becomes polar)
7 0
4 years ago
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If exactly 59.6 g of nitrogen gas is needed to inflate your air bag to the
Inga [223]

Answer:

We need 92.3 grams of sodium azide

Explanation:

Step 1: Data given

Mass of nitrogen gas = 59.6 grams

Molar mass of nitrogen gas = 28.0 g/mol

Molar mass of sodium azide = 65.0 g/mol

Step 2: The balanced equation

2NaN3 → 2Na + 3N2

Step 3: Calculate moles nitrogen gas

Moles N2 = mass N2 / molar mass N2

Moles N2 = 59.6 grams/ 28.0 g/mol

Moles N2 = 2.13 moles

Step 4: Calculate moles NaN3

for 2 moles NaN3 we'll have 2 moles Na and 3  moles N2

For 2.13 moles N2 we need 2/3* 2.13 = 1.42 moles NaN3

Step 5: Calculate mass NaN3

Mass NaN3 = Moles NaN3 * molar mass NaN3

Mass NaN3 = 1.42 moles * 65.0 g/mol

Mass NaN3 = 92.3 grams

We need 92.3 grams of sodium azide

7 0
3 years ago
Which statement describes the periodic law?
mr_godi [17]
Answer is: elements in the same group have similar chemical properties.
Periodic law<span> is the arrangement of the </span>elements<span> in order of increasing atomic number.
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3 0
4 years ago
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6. STATEANSWERIN SIG FIGSOR g/cm3. What mass of silver in grams (g) would be required to cover a dimensions of 120.0 ft x 60.0 f
kogti [31]

Answer:

7.0643\times 10^8 grams of silver would be required.

Explanation:

Dimensions of silver mas :

Length = l =  120.0 ft

breadth = b = 60.0 ft

Height = h = 0.33 ft

Volume of silver mass ,V= l × b × h

V=120.0 ft\times 60.0ft\times 0.33 ft=2,376 ft^3=67,278,816 cm^3

1ft^3=28316.8 cm^3

Density of silver,d = 10.5 g/cm^3

Mass = Density\times Volume

m=10.5 g/cm^3\times 67,278,816 cm^3=7.0643\times 10^8 g

7.0643\times 10^8 grams of silver would be required.

7 0
3 years ago
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