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3 years ago

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The Arrhenius plot of the reaction has a downward slope of 1.5 x104. Calculate the time required to reduce the concentration of

A to 10% of its original value at 100oC. g

1 answer:

madam [21]3 years ago

4 0

1.5?10000 10% then add it up

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two samples of water, 10 grams and 50 grams are in sperate cups which of the following properties is different for the two boili

Trava [24]

Answer:

volume

Explanation:

The volume of the two samples of water will be different because volume is the amount of space occupied by a body. It is dependent on the amount of materials it contains.

The 50g sample will have a higher volume compared to the 10g sample.
The boiling point and density are intensive properties and do not depend on the amount of matter present.
Since both samples are from the same source, they will have the same color.

7 0

3 years ago

Read 2 more answers

What is the mole fraction, X, of solute and the molality, m (or b), for an aqueous solution that is 15.0% NaOH by mass?

GalinKa [24]

Hello!

a) The mole fraction of solute of a 15% NaOH aqueous solution can be calculated in the following way:

First, we have to assume that we have 100 grams of solution. This will simplify the calculations.

Now, we know that this solution has 15 grams of NaOH and 85 grams of water. We can calculate the number of moles of each one in the following way:

$molesNaOH= 15 g NaOH*\frac{1molNaOH}{39,997 g NaOH}=0,3750 moles NaOH \\ \\ moles H_2O=85 gH_2O* \frac{1 mol H_2O}{18 g H_2O}=4,7222 moles H_2O$

To finish, we calculate the mole fraction by dividing the moles of NaOH between the total moles:

$X_{NaOH}= \frac{moles NaOH}{total moles}= \frac{0,3750 moles NaOH}{0,3750 moles NaOH+4,7222 molesH_2O} =0,073$

So, the mole fraction of NaOH is 0,073

b) The molality (moles NaOH/ kg of solvent) of a 15% NaOH aqueous solution can be calculated in the following way:

First, we have to assume that we have 100 grams of solution. This will simplify the calculations.

Now, we know that this solution has 15 grams of NaOH and 85 grams (0,085 kg) of water. We can calculate the moles of NaOH in the following way:

$molesNaOH= 15 g NaOH*\frac{1molNaOH}{39,997 g NaOH}=0,3750 moles NaOH$

Now, we apply the definition of molality to calculate the molality of the solution:

$mNaOH= \frac{moles NaOH}{kg_{solvent}}= \frac{0,3750 moles NaOH}{0,085 kg H_2O}=4,41 m$

So, the molality of this solution is 4,41 m

Have a nice day!

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3 years ago

The angular momentum quantum number (l) value of 0 indicates the ________ subshell.

bonufazy [111]

Answer:

indicates the number of subshells

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Sodium acetate<br><br> NaC2H3O2<br><br> SC2H3O2<br><br> Na2C2H3O2

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Answer:

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The reaction of an alcohol with an organic acid produces a compound classified as

Alik [6]

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