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3 years ago

9

You have 100 milliliters of a 0.50 M MgBr2 solution and dilute it to a total volume of 200 milliliters. What is the molarity of

the resulting solution?

1 answer:

slamgirl [31]3 years ago

3 0

The answer is 0.25 M

Use the equation C1V1=C2V2
(.5)(100)=x(200)
x=0.25

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Methane, CH4, would have the lowest boiling point among the three since it has the lowest number of carbon and has no functional groups. Methanol would have the highest boiling point since it has a functional group which contains hydrogen bonding which much stronger than the one in CH3Cl. Hope this helps.<span />

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Answer is: B because it has a lower activation energy.

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A 0.580 g sample of a compound containing only carbon and hydrogen contains 0.480 g of carbon and 0.100 g of hydrogen. At STP, 3

Sati [7]

Answer:

Molecular formula for the gas is: C₄H₁₀

Explanation:

Let's propose the Ideal Gases Law to determine the moles of gas, that contains 0.087 g

At STP → 1 atm and 273.15K

1 atm . 0.0336 L = n . 0.082 . 273.15 K

n = (1 atm . 0.0336 L) / (0.082 . 273.15 K)

n = 1.500 × 10⁻³ moles

Molar mass of gas = 0.087 g / 1.500 × 10⁻³ moles = 58 g/m

Now we propose rules of three:

If 0.580 g of gas has ____ 0.480 g of C _____ 0.100 g of C

58 g of gas (1mol) would have:

(58 g . 0.480) / 0.580 = 48 g of C

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3 years ago

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strojnjashka [21]

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In acid-base titrations carried out in school and college labs, many of the older generation, well-informed teachers told their students that the acid solution should be taken in the burette.

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2 years ago

The road map in the text shows that to convert from one unit to another, you must use the ____ as an intermediate step. ___ conv

jonny [76]

Answer:

Conversion factor;

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Explanation:

Firstly, an intermediate step is to define the conversion factor that will be then used in a conversion technique called dimensional analysis in order to convert from one unit to another. An example of a conversion factor would be, for example, 1 L = 1000 mL, which can be manipulated as a fraction, either $\frac{1 L}{1000 mL}$ or $\frac{1000 mL}{1 L}$ ;
Secondly, in order to convert mass to moles, we need to know the molar mass of a compound which has a units of g/mol (that is, it shows how many grams we have per 1 mole of substance.
Thirdly, Avogadro's constant, $N_A = 6.022\cdot 10^{23} mol^{-1}$ tells us that there is $N_A$ number of molecules or atoms in 1 mole of substance. We need two conversion factors to convert the number of molecules to a mass: firstly, we need to convert the number of molecules into the number of moles using Avogadro's constant and then we need to use the molar mass to convert the moles obtained into mass.

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3 years ago