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Anestetic [448]
3 years ago
8

Solve each equation or formula for the variable specified. 5g+h=h, for g

Mathematics
1 answer:
Vlada [557]3 years ago
8 0

Answer: hope this will help you

Step-by-step explanation:

Plz mark me as brainlist

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HELP PLEASE SOMEONE
Rom4ik [11]
f(x)= \frac{x}{2} -2 and g(x)=2 x^{2} +x-3
(f+g)(x) = \frac{x}{2} -2+2 x^{2} +x-3
combining like terms gives you answer choice B

8 0
3 years ago
What is 7/4 times 7/3
yaroslaw [1]

49/12

Just mulitply the top and the bottom across.

7*7/4*3

49/12

7 0
3 years ago
Marta can vacuum the house in 30 min. It takes her daughter 45 min to vacuum the house. How long would it take them if they
Mamont248 [21]

Answer:

<h2>18mins</h2>

Step-by-step explanation:

This problem is on combined work rate

given that

Marta can vacuum the house in 30 min

then her rate= 1/30

Also, her daughter will take 45 min to vacuum the house

her  daughter's rate will be = 1/45

then the combined work rate is

1/30+1/45=1/T

30+45/30*45=1/T

75/1350= 1/T

1/18=1/T

This means that they will both take 18 minutes working together to vacum a house

8 0
3 years ago
In quadrilateral ABCD, AD is congruent to BC, and AD is parallel to BC. Andre has written a
Dahasolnce [82]

Answer:

AD is Congruent to BC and it's given, (given just means that it was already said or stated, and you don't need to do the work to find it) Angle DAC would be congruent to angle BAC (if that doesn't work, rearrange them to look like angle CAB). AC would be congruent to DB. Triangle ADC would be congruent to triangle BCD by (since i don't know exactly which way the letters are arranged is would either be SAS or SSA) and that's because you know two of the sides are congruent to each other and one angle.

I tried hard to sketch out what the shape looked like based on the information given, and that's because I need a visual of what the shape looks like. Sorry, this took so long to answer.

5 0
1 year ago
Use the Chain Rule to find the indicated partial derivatives. z = x^4 + xy^3, x = uv^4 + w^3, y = u + ve^w Find : ∂z/∂u , ∂z/∂v
k0ka [10]

I'll use subscript notation for brevity, i.e. \frac{\partial f}{\partial x}=f_x.

By the chain rule,

z_u=z_xx_u+z_yy_u

z_v=z_xx_v+z_yy_v

z_w=z_xx_w+z_yy_w

We have

z=x^4+xy^3\implies\begin{cases}z_x=4x^3+y^3\\z_y=3xy^2\end{cases}

and

\begin{cases}x=uv^4+w^3\\y=u+ve^w\end{cases}\implies\begin{cases}x_u=v^4\\x_v=4uv^3\\x_w=3w^2\\y_u=1\\y_v=e^w\\y_w=ve^w\end{cases}

When u=1,v=1,w=0, we have

\begin{cases}x(1,1,0)=1\\y(1,1,0)=2\end{cases}\implies\begin{cases}z_x(1,2)=12\\z_y(1,2)=12\end{cases}

and the partial derivatives take on values of

\begin{cases}x_u(1,1,0)=1\\x_v(1,1,0)=4\\x_w(1,1,0)=0\\y_u(1,1,0)=1\\y_v(1,1,0)=1\\y_w(1,1,0)=1\end{cases}

So we end up with

\boxed{\begin{cases}z_u(1,1,0)=24\\z_v(1,1,0)=60\\z_w(1,1,0)=12\end{cases}}

3 0
3 years ago
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