Set them equal to each other and solve
3x + 39 = 4x +34
-x=-5
X=5
Plug it in
3(5) + 39 = 54
4(5) +34 = 54
For the final angle ,
54 + 54 = 108
180-108 =72
The angle measures are 54,54, and 72
You didn't give the fourth zero, but the answer is still false. If you have a root or an imaginary number as a zero, then its conjugate is also a zero. So if 8i is a zero, then -8i must also be a zero, and if 4i is a zero, then -4i must be a zero, with those zeros and -4, the number of zeroes exceeds the number of zeroes that a fourth degree polynomial can have.
9514 1404 393
Answer:
FH = 16
Step-by-step explanation:
ΔGHE is a 5-12-13 triangle.
ΔEHF is a 3-4-5 triangle with a scale factor of 4, so side FH is 4·4 = 16 units.
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(3, 4, 5), (5, 12, 13), (7, 24, 25), (8, 15, 17) are all commonly used Pythagorean triples. The first two on the list are used in these triangles.
If you like, you can work out the numbers using the Pythagorean theorem, which tells you the square of the hypotenuse is equal to the sum of the squares of the other two sides.
For ΔEHG, that is ...
GE² = EH² + HG²
13² = EH² + 5²
EH² = 13² -5² = 169 -25 = 144
And for ΔEHF, ...
FE² = EH² +HF²
20² = 144 + HF²
400 -144 = HF² = 256
HF = √256 = 16
The length of side FH is 16 units.
Answer:
(14 - x) + (4·x - 22) = 3·x - 8
We are asked to give the exact value of <span>cos(arcsin(one fourth)). In this case, we shift first the setting to degrees since this involves angles. we determine first arc sin of one fourth equal to 14.48 degrees. then we take the cos of 14.48 degrees equal to 0.9682. Answer is 0.9682.</span>
