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3 years ago

V-100 = ? + ?i NEED HELP

Mathematics

1 answer:

nevsk [136]3 years ago

5 0

Answer: V+100

Step-by-step explanation: If your trying to get 0 then there is your answer

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Find the missing measurement for each quadrilateral 5) this is rhombus ABCD

a_sh-v [17]

To find the area of a rhombus, multiply the lengths of the two diagonals and divide by 2 (same as multiplying by 1/2): The sides and angles of a rhombus: The sides of a rhombus are all congruent (the same length.) Opposite angles of a rhombus are congruent (the same size and measure.)

A square has two perpendicular bisectors but a square is not a rhombus (because a rhombus does not have all four angles = 90. Oh, but wait, a rhombus is a square in the same way a rectangle is a square but not the other way around.

4 0

3 years ago

Two life insurance companies determine their premiums using different formulas:

Pie

Answer:

<em>The age at which both companies charge the same premium is 44 years</em>

Step-by-step explanation:

<u>Graph Solution to System of Equations</u>

One approach to solving systems of equations of two variables is the graph method.

Both equations are plotted in the same grid and we find the intersection point(s) of both graphs. Those are the feasible solutions.

The annual premium p as a function of the client's age a for two companies are given as:

Company A: p= 2a+24

Company B: p= 2.25a+13

The graphs of both functions are shown in the image below.

The red line indicates the formula for Company A and the blue line indicates the formula for Company B.

It can be seen that both lines intersect in the point with approximate coordinates of (44,112).

The age at which both companies charge the same premium is 44 years

8 0

3 years ago

Henry has a rope that is 9 meters long. He cuts away a plece that is 1.31 meters long. How long is the remaining plece of rope?

Blababa [14]

Take 9 and subtract 1.31. It equals 7.69 meters

3 0

3 years ago

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How do I find the scale factor

iris [78.8K]

You write it as a ratio eg. SF(large→small)=20:7

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3 years ago

Prove the divisibility of the following numbers:

ratelena [41]

Make use of prime factorizations:

$16^5+2^{15}=(2^4)^5+2^{15}=2^{20}+2^{15}$

Both terms have a common factor of $2^{15}$ :

$16^5+2^{15}=2^{15}\left(2^5+1\right)=2^{15}\cdot33$

- - -

The second one is not true! We can write

$15^7+5^{13}=(3\cdot5)^7+5^{13}=3^7\cdot5^7+5^{13}$

Both terms have a common factor of $5^7$ :

$15^7+5^{13}=5^7\left(3^7+5^6\right)$

Since $30=5\cdot6$ , and $5\mid5^7$ , we'd still have to show that $5^6(3^7+5^6)$ is a multiple of 6. This is impossible, because $6=3\cdot2$ and there is no multiple of 2 that can be factored out.

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3 years ago

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