The question here is how long does it take for a falling
person to reach the 90% of this terminal velocity. The computation is:
The terminal velocity vt fulfills v'=0. Therefore vt=g/c,
and so c=g/vt = 10/(100*1000/3600) = 36,000/100,000... /s. Incorporating the
differential equation shows that the time needed to reach velocity v is
t= ln [g / (g-c*v)] / c.
With v=.9 vt =.9 g/c,
t = ln [10] /c = 6.4 sec.
Answer:
see the picture below
Step-by-step explanation:
There is 19, 13, 8, 4, 7, 14, 7, 9.
There is 1 number between 0 and 5.
and there's 4 on between 6 to 10.
and so far.
<h2>Answer :</h2>
Let the number be x. Then according to the question,
Step 1 :- Adding 3
=> x + 3
Step 2 :- Multiply the sum by 2
=> 2×(x + 3)
Step 3 :- Subtract 6
=> 2(x +3) - 6
<h3>Thus the expression becomes 2(x +3) - 6. </h3>
Answer:
158.4 i think
Step-by-step explanation:
