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Given data is 54, 59, 35, 41, 46, 25, 47, 60, 54, 46, 49, 46, 41, 34, 22
Arranging it in increasing order:
22 25 34 35 41 41 46 46 46 47 49 54 54 59 60
Number of data items, n=15.
Finding Median, First Quartile, and Third Quartile
22 25 34 35 41 41 46 46 46 47 49 54 54 59 60
Now finding First Quartile from set: 22 25 34 35 41 41 46
Q₁ = middle term i.e. 35
Now finding Third Quartile from set: 46 47 49 54 54 59 60
Q₃ = middle term i.e. 54
So we have Q₁ = 35, M = 46, and Q₃ = 54. Lower bound is 22 and Upper bound is 60.
While drawing the given data on number line and marking First quartile, Median, Third quartile on number line. We can clearly observe that option A matches with given data points.
Hence, option A i.e. Box-plot A is the correct choice.
Using the normal distribution, it is found that 95.15% of students receive a merit scholarship did not receive enough to cover full tuition.
<h3>Normal Probability Distribution</h3>The z-score of a measure X of a normally distributed variable with mean and standard deviation
is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation for the amounts are given as follows:
The proportion is the <u>p-value of Z when X = 4250</u>, hence:
Z = 1.66
Z = 1.66 has a p-value of 0.9515.
Hence 95.15% of students receive a merit scholarship did not receive enough to cover full tuition.
More can be learned about the normal distribution at brainly.com/question/15181104
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