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MaRussiya [10]
3 years ago
10

1. How many moles of oxygen gas are required to react with 15.56 moles of hydrogen gas? (2 pts.)

Chemistry
1 answer:
loris [4]3 years ago
7 0

Answer:

7.78moles of O2

Explanation:

2H2 (g) + O2 (g) → 2H2O (g)

From the balanced equation,

2 moles of H2 required 1mole of O2.

Therefore, 15.56 moles of H2 will require = 15.56/2 = 7.78moles of O2

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Oxygen decays to form nitrogen. 15 8 O → 15 7 N + 0 1 e This type of nuclear decay is called
Natasha2012 [34]

The type of nuclear decay in which Oxygen decays to form nitrogen is beta plus decay.

<h3>What is a beta plus decay?</h3>

A beta plus decay is a type of decay in which a proton in an element disintegrates to produce a neutron resulting in a decrease in the atomic number of the radioactive element.

In the given equation below:

  • ^{15}_{7}O \rightarrow ^{15}_{7}N + ^{0}_{1}e

Oxygen decays to form nitrogen due to a decrease in atomic number.

This is an example of beta plus decay.

In conclusion, oxygen decays to form nitrogen beta plus decay.

Learn more about beta plus decay at: brainly.com/question/12448836

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5 0
2 years ago
Now look at the volcano map what type of boundary tends to give rise to volcanic activity
DochEvi [55]
Divergent and convergent plate boundaries cause volcanic activity
8 0
3 years ago
To identify a diatomic gas (X2), a researcher carried out the following experiment: She weighed an empty 3.6-L bulb, then filled
aleksandrvk [35]

Answer:

The gas was N₂

Explanation:

V = 3.6L

P = 2.0 atm

T = 24.0°C = 297K

R = 0.0821 L.atm/K.mol

m = 8.3g

M = molar mass = ?

Using ideal gas equation;

PV = nRT

n = no. Of moles = mass / molar mass

n = m/M

PV = m/M * RT

M = mRT / PV

M = (8.3*0.0821*297) / (2.0*3.6)

M = 28.10

Since X is a diatomic molecule

M = 28.10 / 2 = 14.05 g/mol

M = Nitrogen

X = N₂

5 0
3 years ago
Given a container of helium gas with an initial volume of
Gnoma [55]

Answer:

v2 = 3.9 L

Explanation:

3 0
3 years ago
What causes pressure inside a helium balloon?
kupik [55]

Explanation:

So the gas pressure of a helium balloon arises from the impact of the collisions of the helium atoms between themselves and with the inside surface of the balloon. Of course, the outside atmosphere similarly exerts a pressure on the outside of the balloon.

7 0
3 years ago
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