How many moles of air must escape from a 10-m 8.0-m 5.0-m room when the temperature is raised from 0c to 20c? assume the p
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5.911 grams of manganese dioxide and 1.224 gram of water are consumed.
<h3>What is Balanced Chemical Equation ?</h3>The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
The given reaction balanced equation is:
Zn(s) + MnO₂(s) + H₂O(l) → ZnO(s) + Mn(OH)₂(s)
<h3>How to find the number of moles ?</h3>To find the number of moles use the expression:
Number of moles =
Here,
Mass of Zn = 4.50 g
Molar mass of Zn = 65.4 g/mol
Now put the value in above expression
Number of moles of Zn =
=
= 0.068 mol
Mass of MnO₂ = Moles of MnO₂ × Molar mass of MnO₂
= 0.068 mol × 86.9368 g/mol
= 5.911 g
Mass of H₂O = Moles of H₂O × Molar mass of H₂O
= 0.068 mol × 18.0 g/mol
= 1.224 g
Thus from the above conclusion we can say that 5.911 grams of manganese dioxide and 1.224 gram of water are consumed.
Learn more about the Balanced chemical equation here: brainly.com/question/26694427
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