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ludmilkaskok [199]
3 years ago
8

Which part of a chemical formula indicates the number of atoms of an element that make up a molecule? A. plus signs B. subscript

s C. coefficients D. chemical symbols
Chemistry
2 answers:
krok68 [10]3 years ago
8 0

<u>Answer:</u> The correct answer is Option B.

<u>Explanation:</u>

For the given options:

<u>Option A:</u> Plus sign is written in a chemical equation to show the number of chemical species reacting or getting produced.

Option B: Subscript numbers are defined as the number of atoms of each element present in a compound.

For Example: In H_2O, 2 atoms of hydrogen element is there and 1 atom of oxygen element is there.

<u>Option C:</u> Coefficients are defined as the numbers which are written in front of the atoms or molecules in a chemical reaction. They represent the number of moles of substance in a chemical reaction.

<u>Option D:</u> Chemical symbols are used to write the short form of the elements.

Hence, the correct answer is Option B.

Elina [12.6K]3 years ago
5 0

Hey there!

I believe the answer you are looking for is D.

If i am incorrect, I am very sorry. I would love any feedback!

Have a nice day and Happy Halloween!

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A 100. 0 ml sample of 0. 10 m nh3 is titrated with 0. 10 m hno3. Determine the ph of the solution after the addition of 100. 0 m
DerKrebs [107]

The pH of the solution after the addition of 100. 0 ml of HNO3. The kb of NH3 is 1. 8 × 10-5. So, pH is 10.9 basic .

This neutralization occurs as the acid is added to the base:

NH3(aq)+ HNO3(aq)= NH4NO3(aq)+ H2O(l)

The initial moles of NH3present is given by,

nNH3= c×v= 0.10× 100/1000= 0.01m

The number of moles of

HNO3 added is given by:

nHNO3= c×v= 0.10× 100/1000= 0.001

It is clear from the equation that the acid and base react in a 1:1 molar ratio. So, the no. moles of NH3remaining will be 0.01 - 0.001= 0.009

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The concentration of NH3 is given by,

[NH3]= c/v= 0.001/200/1000= 0.05x mol/l .

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where b is the base's concentration.

Given that there is little dissociation, we can roughly compare this to the starting concentration.

pKb= −logKb= −log(1.8×10−5)= 4.744

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8 0
1 year ago
How many grams of oxygen are required to burn 60 grams of ethane gas, C2H6? 2 C2H6 (g) + 7 O2(g) → 4 CO2 (g) + 6 H2O (g)
timofeeve [1]
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Answer:

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