Answer:
10.2 cM
Explanation:
Given,
pure breeding parent 1 : BBgg = brown coat and pink eyes
pure breeding parent 2 : bbGG = white coat and green eyes
BBGG X bbgg = F1 = BbGg ( All are brown with green eyes )
When F1 progeny is test crossed with white coat and pink eyes hamster:
BbGg X BbGg = F2 =
brown, pink eyes = 99 = parental
white, green eyes = 103 = parental
brown, green eyes = 12 = recombinant
white, pink eyes = 11 = recombinant
Recombination frequency =
(total number of recombinants / total progeny ) * 100
= [( 11 + 12 ) / ( 99 + 103 + 12 + 11 )] * 100 = (23/225)*100 = 0.102 * 100 = 10.2 %
1 % recombination frequency = 1 cM distance between genes
Hence, the distance between B and G gene is 10.2 cM
