Interpreting I know of at least sign language the state is requiring you to be certified in order to have that occupation.
<span>Random access memory.
This problem requires you to know what the different types of memory are and their relative advantages and disadvantages. Let's look at them and see why 3 are wrong and one is correct.
read-only memory: Otherwise known as ROM, this type of memory stores code that can't be over written. Used frequently for constant lookup values and boot code. Since it can't be written to by normal programs, it can't hold temporary values for Samantha. So this is the wrong choice.
random-access memory: Otherwise known as RAM, this type of memory is used to store temporary values and program code. It is quite fast to access and most the immediately required variables and program code is stored here. It can both be written to and read from. This is the correct answer.
hard disk: This is permanent long term readable and writable memory. It will retain its contents even while powered off. But accessing it is slow. Where the contents of RAM can be accessed in nanoseconds, hard disk takes milliseconds to seconds to access (millions to billions of times slower than RAM). Because it's slow, this is not the correct answer. But it's likely that Samantha will save her spreadsheet to hard disk when she's finished working with it so she can retrieve the spreadsheet later to work on again.
compact disk: This is sort of the ROM equivalent to the hard disk. The data stored on a compact disk can not be over written. One way of describing the storage on a compact disk is "Write Once, Read many times". In most cases it's even slower than the hard disk. But can be useful for archiving information or making backups of the data on your computer.</span>
Explanation:
well that happened to me to and what my dad did was to cut the cable and fix it,it worked.Ithink my situation is very different than yours but you cantiue to see what else it says and if you want to you can text me back.
Answer:
Explanation:
try
clc
clear
close all
x=linspace(0,2*pi,7);
z=cos(pi.*x./3)
% the output on mine is to 4 decimals so it looks a bit different than what the output on your example is , but, I think if you change the format to decimal 2 it will look the same :)
The answer is C) Availability.
Although the company is addressing scalability by adding more servers, the question is asking for security requirement. Therefore we need to choose one of the principles from CIA triad which includes confidentiality, integrity, and availability.
Integrity involves keeping the data accurate and confidentiality involves keeping the data between the sender and intended recipient(s). That being said, scalability and availability are the possible answers.
C) Availability is the best answer because it is part of the CIA triad.
Note: Another resource to look at for cyber security principles would be the Parkerian Hexad.
